0^9 +7x+189yx−3y
o
9
+7x−3y
9
+7x+3y
9
−7x−3y
9
−7x+3y
9
+7x+189yx−3y
2 Collect like terms.
{o}^{9}+(7x+7x-7x-7x+7x)+(-3{y}^{9}+3{y}^{9}-3{y}^{9}+3{y}^{9})+189yx-3y
o
9
+(7x+7x−7x−7x+7x)+(−3y
9
+3y
9
−3y
9
+3y
9
)+189yx−3y
3 Simplify.
{o}^{9}+7x+189yx-3y
o
9
+7x+189yx−3y
Answer:
no of kernels pop = 4.34
Step-by-step explanation:
given data
kernels pop in 5 second = 12
kernels are present = 235
solution
we get here kernels are pop at rate of here
kernels are pop at rate = 12 ÷ 235
kernels are pop at rate = 0.051063
and
we get here maximum kernels are remaining that is
maximum kernels remaining = 235 - 140
maximum kernels remaining = 85
so
no of kernels pop in 5 second will be
no of kernels pop = 0.051063 × 85
no of kernels pop = 4.34
Answer:
90 km/h
Step-by-step explanation:
To solve this problem you first need to convert minutes to hours since the unit is km/h. Doing this we get half an hour (1 hour=60 mins so you divide 30 by 60) after converting you simply divide 45 by 1/2 or .5 to get the answer.
