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barxatty [35]
3 years ago
12

Need an answer asap!!!! a = 12, b = 5, and c = 4. 3c + bc - 2a

Mathematics
1 answer:
Serhud [2]3 years ago
6 0

Answer:

8

Step-by-step explanation:

3(4)+(5)(4)-2(12)

then solve

12+20-24=8

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When an object moves in a circle the __________ of the object is continually changing. What is the missing word in this sentence
Bezzdna [24]

Answer:

velocity

Step-by-step explanation:

The velocity of the object is continually changing.  This velocity is the slope of the tangent line to the curve at a given point on the curve.

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2 years ago
(98 points) BEST EXPLANATION + CORRECT ANSWER GETS BRAINLIEST!
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It's a vertical angle. Add the two angles 143+33=176
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4 0
3 years ago
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We used these functions to represent the two sides of the equation:
katrin [286]

The solution to the system of equation graphed is (-1, -3)

<h3>Solution to system of equation</h3>

Given the system of equations graphed on the plane expressed as:

f(x) = 3x

g(x) = 4x + 1

Equate

f(x) = g(x)

3x = 4x + 1

3x - 4x = 1

-x = 1

x = -1

Determine the value of y

y = 3x

y = 3(-1)

y = -3

Hence the solution to the system of equation graphed is (-1, -3)

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4 0
2 years ago
The sum of a number and three more than the number.
Likurg_2 [28]

Answer:

3x

Step-by-step explanation:

7 0
2 years ago
What is the volume of a cylinder in cubic feet with a height of 8 feet and a base diameter of 18 feet
postnew [5]

Answer:

The volume of a cylinder:

V \approx 2035.75 ft^3

Step-by-step explanation:

-To find the volume of a cylinder, you first need the formula:

V = \pi (\frac{d}{2})^2  h

d = diameter

h = height

-Use the following diameter and height for the formula:

V = \pi (\frac{18}{2})^2  8

-Then, you solve:

V = \pi (\frac{18}{2})^2  8

V = \pi \times (\frac{18}{2})^2 \times  8

V = \pi \times (9)^2 \times  8

V = \pi \times 81 \times  8

V = \pi \times 648

V = 648\pi \approx 2035.752

-Since the hundredth place is 2, It cannot be rounded to the nearest hundredths place, so it would be:

V \approx 2035.75 ft^3

8 0
3 years ago
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