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vaieri [72.5K]
2 years ago
11

A dog is on the ground watching a cat on a 6-foot-

Mathematics
1 answer:
timofeeve [1]2 years ago
3 0

Answer:

5.0344

Step-by-step explanation:

tan=opposite

      adjacent

Since you're trying to find the adjacent side to the angle 50, use tan.

So tan 50º= 6/x

Swap x and tan 50º , which puts tan 50º under the 6.

Use your calculator to find the approximate value of tan 50º (rounded to 4 decimals)

Then divide!

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Find the mean and median of these data: 2, 5, 9, 11, 17, 19.
Harrizon [31]
<span>data: 2, 5, 9, 11, 17, 19
</span>
median is the middle number
median = (9+11)/2 = 10

mean = average
mean = (2 + 5 + 9 + 11+  17 + 19)/6
mean = 63/6
mean = 10.5
6 0
3 years ago
1/2+(-5/8) please help me I really need help have a great day
daser333 [38]

Answer:

-0.125

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A punch glass is in the shape of a hemisphere with a radius of 5 cm. If the punch is being poured into the glass so that the cha
Galina-37 [17]

Answer:

28.27 cm/s

Step-by-step explanation:

Though Process:

  • The punch glass (call it bowl to have a shape in mind) is in the shape of a hemisphere
  • the radius r=5cm
  • Punch is being poured into the bowl
  • The height at which the punch is increasing in the bowl is \frac{dh}{dt} = 1.5
  • the exposed area is a circle, (since the bowl is a hemisphere)
  • the radius of this circle can be written as 'a'
  • what is being asked is the rate of change of the exposed area when the height h = 2 cm
  • the rate of change of exposed area can be written as \frac{dA}{dt}.
  • since the exposed area is changing with respect to the height of punch. We can use the chain rule: \frac{dA}{dt} = \frac{dA}{dh} . \frac{dh}{dt}
  • and since A = \pi a^2 the chain rule above can simplified to \frac{da}{dt} = \frac{da}{dh} . \frac{dh}{dt} -- we can call this Eq(1)

Solution:

the area of the exposed circle is

A =\pi a^2

the rate of change of this area can be, (using chain rule)

\frac{dA}{dt} = 2 \pi a \frac{da}{dt} we can call this Eq(2)

what we are really concerned about is how a changes as the punch is being poured into the bowl i.e \frac{da}{dh}

So we need another formula: Using the property of hemispheres and pythagoras theorem, we can use:

r = \frac{a^2 + h^2}{2h}

and rearrage the formula so that a is the subject:

a^2 = 2rh - h^2

now we can derivate a with respect to h to get \frac{da}{dh}

2a \frac{da}{dh} = 2r - 2h

simplify

\frac{da}{dh} = \frac{r-h}{a}

we can put this in Eq(1) in place of \frac{da}{dh}

\frac{da}{dt} = \frac{r-h}{a} . \frac{dh}{dt}

and since we know \frac{dh}{dt} = 1.5

\frac{da}{dt} = \frac{(r-h)(1.5)}{a}

and now we use substitute this \frac{da}{dt}. in Eq(2)

\frac{dA}{dt} = 2 \pi a \frac{(r-h)(1.5)}{a}

simplify,

\frac{dA}{dt} = 3 \pi (r-h)

This is the rate of change of area, this is being asked in the quesiton!

Finally, we can put our known values:

r = 5cm

h = 2cm from the question

\frac{dA}{dt} = 3 \pi (5-2)

\frac{dA}{dt} = 9 \pi cm/s// or//\frac{dA}{dt} = 28.27 cm/s

5 0
3 years ago
Tim and Tom are trying to earn money to buy a new game system over a 3-month period. Tim saved $45.34 each month. If they need a
Readme [11.4K]
45.34 X 3= 136.02
212.52 - 136.02= 76.50
76.50/3= 25.50

the answer is $25.50
8 0
3 years ago
A pyramid-shaped tent has a square base with sides that are 4 ft long. If the tent is 6 ft tall, what is the volume of the tent?
Dmitry_Shevchenko [17]
The volume of the tent would be 96ft^3, this is because the equation for volume is Length x Width x Hight, so (4)(4)(6) which makes 96
6 0
3 years ago
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