49+49=98
do you need more answers than that?? cause there are almost an infinite range of what can equal 98 when added together..
Answer:
m∠MON = 15°
Step-by-step explanation:
The given parameters are;
m∠LON = 77°
m∠LOM = 9·x + 44°
m∠MON = 6·x + 3°
By angle addition postulate, we have;
m∠LON = m∠LOM + m∠MON
Therefore, by substituting the known values, we have;
∴ 77° = 9·x + 44° + 6·x + 3°
77° = 9·x + 44° + 6·x + 3° = 15·x + 47°
77° = 15·x + 47°
77° - 47° = 15·x
15·x = 77° - 47° = 30°
15·x = 30°
x = 30°/15 = 2°
x = 2°
Given that m∠MON = 6·x + 3° and x = 2°, we have;
m∠MON = 6 × 2° + 3° = 12° + 3° = 15°
m∠MON = 15°.
*Given
Money of Phoebe - 3 times as much as Andy
Money of Andy - 2 times as much as Polly
Total money of Phoebe, - <span>£270
</span> Andy and Polly
*Solution
Let
B - Phoebe's money
A - Andy's money
L - Polly's money
1. The money of the Phoebe, Andy, and Polly, when added together would total <span>£270. Thus,
</span>
B + A + L = <span>£270 (EQUATION 1)
2. Phoebe has three times as much money as Andy and this is expressed as
B = 3A
3. Andy has twice as much money as Polly and this is expressed as
A = 2L</span> (EQUATION 2)
<span>
4. This means that Phoebe has ____ as much money as Polly,
B = 3A
B = 3 x (2L)
B = 6L </span>(EQUATION 3)<span>
This step allows us to eliminate the variables B and A in EQUATION 1 by expressing the equation in terms of Polly's money only.
5. Substituting B with 6L, and A with 2L, EQUATION 1 becomes,
6L + 2L + L = </span><span>£270
</span> 9L = <span>£270
</span> L = <span>£30
So, Polly has </span><span>£30.
6. Substituting L into EQUATIONS 2 and 3 would give us the values for Andy's money and Phoebe's money, respectively.
</span>
A = 2L
A = 2(£30)
A = £60
Andy has £60
B = 6L
B = 6(£30)
B = £180
Phoebe has £180
Therefore, Polly's money is £30, Andy's is £60, and Phoebe's is £180.
Answer:
-6, -4, 4, 8
Step-by-step explanation:
hope it helps <3
