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tester [92]
3 years ago
15

Write the equation of a horizontal line that passes through the point (3,-3).

Mathematics
1 answer:
cestrela7 [59]3 years ago
4 0
Hello : 
 the equation is : y -(-3) = 0(x-3)....(slope = 0 '<span>horizontal line')
y=-3</span>
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Find the modal class interval.
photoshop1234 [79]

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Step-by-step explanation:

The modal class interval is the class interval with the highest frequency, the highest frequency from the table is 8 , which belongs to the class interval 24≤ a < 26

4 0
3 years ago
I need help to find m
Neko [114]

Answer:

∠MNO = 75°

Step-by-step explanation:

∠mno = 1/2 ( arc MLP - arc MOP )

arc MLP = 241 and arc MOP = 91

so ∠MNO = 1/2 ( 241 - 91 )

241 - 91 = 150

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4 0
2 years ago
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(5a^2+6a+2)-(7a^2-7a-5)
krok68 [10]

For this case we must simplify the following expression:(5a^ 2 + 6a + 2) - (7a^ 2-7a-5) =

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- * + = -\\- * - = +

So:

5a ^ 2 + 6a + 2-7a ^ 2 + 7a + 5 =

We add similar terms taking into account that:

Equal signs are added and the same sign is placed.

Different signs are subtracted and the major sign is placed.

5a ^ 2-7a^2 + 6a + 7a +2 +5 =\\-2a ^ 2 + 13a + 7

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-2a ^ 2 + 13a + 7

8 0
3 years ago
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8_murik_8 [283]
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8 0
3 years ago
GUYS PLEASE HELP
Volgvan

Answer:

10 minutes

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If you put the 2 equations in your calculator, the intersection will happen at x=10, showing that you and your friend will have an equal number of flyers at 10 minutes.

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3 years ago
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