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Gennadij [26K]
2 years ago
14

Can someone please help me??

Mathematics
1 answer:
olga2289 [7]2 years ago
5 0
You would have to multiply then subtract
30% is .30
Multiply 18.75 and .30
which is $5.63
Then subtract 18.75 from 5.63
Which the final ANSWER is: $13.12
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-1/2x+3y=-3 in slope intercept form​
ElenaW [278]

Answer:

Step-by-step explanation:

Y = mx + b

-1/2 x + 3y = -3

3y = 1/2 x -3

y = 1/6 x - 1

Where slope m = 1/ 6and y intercept b = -1

8 0
2 years ago
Generate two equivalent fractions for each fraction. Use fraction tikes or number lines.<br> 1/3
Romashka [77]
Equivealent= like 

6/18, 5/15
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4 0
2 years ago
Simplify your answer to the previous part and enter a differential equation in terms of the dependent variable xx satisfied by x
rusak2 [61]

Answer:

x'-5x=0, or x''-25x=0, or x'''-125x=0

Step-by-step explanation:

The function x(t)=e^{5t} is infinitely differentiable, so it satisfies a infinite number of differential equations. The required answer depends on your previous part, so I will describe a general procedure to obtain the equations.

Using rules of differentiation, we obtain that x'(t)=5e^{5t}=5x \text{ then }x'-5x=0. Differentiate again to obtain, x''(t)=25e^{5t}=25x=5x' \text{ then }x''-25x=0=x''-5x'. Repeating this process, x'''(t)=125e^{5t}=125x=25x' \text{ then }x'''-125x=0=x'''-25x'.

This can repeated infinitely, so it is possible to obtain a differential equation of order n. The key is to differentiate the required number of times and write the equation in terms of x.

7 0
2 years ago
Is this Statement true or false?
nikitadnepr [17]

Answer:

True

Step-by-step explanation:

Yes, this is True because dotted lines are not part of the solution on a graph.

Sorry! Can't be explained more than this!

3 0
3 years ago
Read 2 more answers
Approximate 188 to near hundreth
kipiarov [429]

Answer:

200

Step-by-step explanation:

we look at the tens place which is 8 since it greater than 5 we turn 8 and the number after into zeros and the 1 into a 2.

hope this welps :3

6 0
3 years ago
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