Help with #4 please

Use the numbers 5,6, and 7 and the operations of addition,subtraction, multiplication, and/or division to create three different

mars1129 [50]

1. 5x6+7

2. 6x7+5

3. 5x7+6

Hope I helped :)

5 0

3 years ago

Read 2 more answers

!!!!!!!!!!!!!!!!!!!!

notsponge [240]

Option 3

The solution for given expression is $\frac{(x - 4)(x - 4)}{(x + 3)(x + 1)}$

<h3><u>Solution:</u></h3>

Given that we have to divide,

$\frac{x^2 -16}{x^2 + 5x + 6} \div \frac{x^2 + 5x + 4}{x^2 -2x - 8}$ ---- (A)

Let us first factorize each term and then solve the sum

Using $a^2 - b^2 = (a + b)(a - b)$

$x^2 -16 = x^2 - 4^2 = (x + 4)(x -4)$ ----- (1)

$x^2 + 5x + 6 = (x + 2)(x + 3)$ ----- (2)

$x^2 + 5x + 4 = (x+1)(x + 4)$ ---- (3)

$x^2 -2x - 8 = (x-4)(x + 2)$ ---- (4)

Now substituting (1), (2), (3), (4) in (A) we get,

$\frac{(x + 4)(x -4)}{(x +2)(x +3)} \div \frac{(x+1)(x+4)}{(x-4)(x +2)}$

To do division with fractions, we turn the second fraction upside down and change the division symbol to a multiplication symbol at the same time. Then we treat this as a multiplication problem, by multiplying the numerators and the denominators separately.

$\frac{(x + 4)(x -4)}{(x +2)(x +3)} \times \frac{(x - 4)(x + 2)}{(x + 1)(x + 4)}$

On cancelling terms we get,

$= \frac{(x -4)(x-4)}{(x + 3)(x + 1)}$

Thus option 3 is correct

6 0

4 years ago

Solve the equation: <img src="https://tex.z-dn.net/?f=5%5Ex%5E%28%5Ex%5E-%5E1%5E%29%3D1" id="TexFormula1" title="5^x^(^x^-^1^)=1

Tomtit [17]

<u>The concept:</u>

We are given the equation:

$5^{x(x-1)} = 1$

Which can be simplified as:

$5^{x^{2} - x} = 1^{1}$

Since any number to the power '0' is 1

x² - x must be equal to 0 for the given equation to be true

<u></u>

<u>Solving for x:</u>

x² - x = 0

x(x-1) = 0

now, we can divide both sides by either x OR x-1

So we will see what we get for either choice:

x = 0/(x-1) x-1 = 0/x

x = 0 x = 1

Hence, the value of x is either 0 or 1

7 0

3 years ago

Your blank should furnish enough money to live on, in an emergency, for six months

Bond [772]

C. Savings.

It's often recommended that you have a savings account/emergency fund with roughly 3-6 months worth of living expenses in case of an emergency.

8 0

3 years ago

Read 2 more answers

PLEASE HELP!!!!! I DON'T UNDERSTAND!!

Roman55 [17]

Answer: Pool Size

(in feet) 3.5 ft

Avg Depth 4 ft

Avg Depth 4.5 ft

Avg Depth 5 ft

Avg Depth

12x24 7,600 8,600 9,700 10,800

14x28 10,300 11,800 13,200 14,700

15x30 11,800 13,500 15,200 16,900

16x32 13,400 15,400 17,300 19,200

18x36 17,000 19,400 21,900 24,300

19x38 19,000 21,700 24,400 27,100

20x40 21,000 24,000 27,000 30,000

22x44 25,400 29,000 32,700 36,300

25x45 29,531 33,750 37,968 42,187

25x50 32,800 37,500 42,200 46,900

30x50 39,375 45,000 50,525 56,250

Step-by-step explanation:I made this chart for you so you can know actually how to multiply the width of the pool.

6 0

3 years ago