How to find rapidly the coordinates of Q:
since Q is the center of gravity of the triangle ABC, so we have the following vector relationship
vecQA +vecQB +vecQC =<span>vec0
</span><span>vecQA=(x-3, y+2)
</span><span>vecQB=(x-1, y+5)
</span><span>vecQC=(x-7, y+5)
</span><span>vec0=(0, 0)
</span>
so, vecQA +vecQB +vecQC =<span>vec0 is equivalent to
</span>x-3 +x-1+x-7 =0, and y+2+y+5+<span>y+5=0 so 3x-11=0 implies x=11/3
</span><span>and 3y+12=0 implies y=-12/3
finally the </span><span>the coordinates of point Q is (11/3, -4)</span><span>
</span>
Idk tbh man I think sumbody else will answer
Energy in the form of HEAT
Answer:
and also mark me the brainliest for the answer
Step-by-step explanation:
Answer:
C, D, and E are correct
Step-by-step explanation:
p(2)= 1/6; p(3)= 1/6; p(4)= 1/6; 1/6=1/6=1/6
p(1)= 3/6; 3/6=1/2
p(4) = 1/6; There are six sections and one section is labeled<em> '4' </em>
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Hope this helped! ;p