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frez [133]
3 years ago
13

"The goal during digestion is to break carbohydrates, proteins, and lipids down into smaller units, including ____."

Biology
1 answer:
Viktor [21]3 years ago
4 0

Glucose,  amino acids, lipids and glycerol.

Explanation:

Carbohydrate is broken into glucose molecules

protein is  broken into amino acids

Lipid is broken into fatty acids and glycerol.

Starch present in the food is broken to glucose molecules to yield energy.

Protein is digested in stomach by the action of pepsin, trypsin and chymotrypsin.

Glycosidic bonds of starch is broken down by salivary and pancreatic amylase enzyme.

fat is acted upon by lipase enzymes from pancreatic and intestinal juices.

these are broken into smaller units so that gets absorbed by blood and carries throughout the body.

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I NEED HELP WITH THIS BIOLOGY QUESTION
nataly862011 [7]
C, the first two don't make sense and the last one would support the opposing view point.
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We are studying 3 strains of bacteria, with populations p1, p2, p3, in an environment with three food sources, A, B, C. In a day
Nastasia [14]

Answer:

The population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.

Explanation:

From the given information:

For  food source A; we have:

3P₁ + P₂ + 2P₃ = 58    units of food A ---- (1)

For food source B; we have:

2P₁ + 4P₂ + 2P₃ = 70   units of food B  ---- (2)

For food source C; we have:

P₁ + P₂  = 20   units of food C    ----- (3)

From equation (1) and (2); we have:

3P₁ + P₂ + 2P₃ = 58

2P₁ + 4P₂ + 2P₃ = 70

By elimination method

 3P₁ + P₂ + 2P₃ = 58

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 2P₁ + 4P₂ + 2P₃ = 70

<u>                                       </u>

<u> P₁  -   3P₂   + 0    = - 12    </u>

P₁ = -12 + 3P₂   ---- (4)

Replace, the value of P₁  in (4) into equation (3)

P₁ + P₂  = 20

-12 + 3P₂ + P₂  = 20

4P₂ = 20 + 12

4P₂ = 32

P₂ = 32/4

P₂ = 8

From equation (3) again;

P₁ + P₂  = 20

P₁ + 8 = 20

P₁  = 20 - 8

P₁  = 12

To find P₃;  replace the value of P₁ and P₂ into (1)

3P₁ + P₂ + 2P₃ = 58

3(12) + 8 + 2P₃ = 58

36 + 8 + 2P₃ = 58

2P₃ = 58 - 36 -8

2P₃ = 14

P₃ = 14/2

P₃ =  7

Thus, the population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.

4 0
3 years ago
The life history pattern in which population growth is logistic is called
KIM [24]
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