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3 years ago

How do I sketch the graph y=-x?

Mathematics

1 answer:

pashok25 [27]3 years ago

6 0

x y
-1 1
-2 2
-3 3
---------------
x y
1 -1
2 -2
3 -3

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What is the smallest positive integer n such that n! ends in at least 2019 zeros?

Lady_Fox [76]

Answer:

I think there's 502

Step-by-step explanation:

if this is a olunomical question that should be it I believe, because you have to write in standered form then when it equals zero, then factor it

3 0

1 year ago

Break apart addendsas tens and ones <br> 33<br> +49

Serhud [2]

Answer:

There are 8 tens and 2 ones

Step-by-step explanation:

Hope this helps

5 0

3 years ago

Chang is estimating the volume of his bathtub the actual volume of his bathtub is 37 gal chang’s estimate is 31 gal find the abs

stepladder [879]

<h3>The absolute error is 6</h3><h3>The percent error is 16.22 %</h3>

<em><u>Solution:</u></em>

Given that,

Actual volume of his bathtub is 37 gal

Estimate is 31 gal

<em><u>Find the absolute error</u></em>

Absolute Error = | Measured Value - Actual Value |

Absolute Error = | 31 - 37 |

Absolute Error = 6

<em><u>Find the percent error</u></em>

$Percent\ error = \frac{\text{estimate - actual}}{actual} \times 100$

Substituting we get,

$percent\ error = \frac{31-37}{37} \times 100\\\\percent\ error = \frac{-6}{37} \times 100\\\\percent\ error = -16.22$

Negative sign means percent decrease

Thus percent error is 16.22 %

5 0

2 years ago

Can somebody help with these three questions plz

liraira [26]

$\bf \sqrt{2}\left(3\sqrt{2}+\sqrt{18} \right)~~
\begin{cases}
18=2\cdot 3\cdot 3\\
\qquad 2\cdot 3^2
\end{cases}\implies \sqrt{2}\left(3\sqrt{2}+\sqrt{2\cdot 3^2} \right)
\\\\\\
\sqrt{2}\left(3\sqrt{2}+3\sqrt{2} \right)\implies \sqrt{2}\left(6\sqrt{2} \right)\implies 6\left(\sqrt{2}\right)^2\implies 6\cdot 2\implies \stackrel{rational}{12}$

7 0

3 years ago

Please Help!!

algol13

When you see questions of this nature, test the individual inequalities and look out for their intersection.

For
$y < \frac{2}{3} x$
Choose a point in the lower or upper half plane created by the line
$y = \frac{2}{3} x$
The above line is the one which goes through the origin.

Now testing (1,0) yields,

$0 < \frac{2}{3} (1)$
That is,

$0 < \frac{2}{3}$
This statement is true. So we shade the lower half of
$y = \frac{2}{3} x$

For
$y \geqslant - x + 2$
We test for the origin because, it is not passing through the origin.

$0 \geqslant - (0) + 2$
This yields
$0 \geqslant 2$
This statement is false so we shade the upper half.

The intersection is the region shaded in B. The top right graph

8 0

3 years ago