2560000 sequences of answers are possible.
<em><u>Explanation</u></em>
Total number of questions = 10
First 4 questions have 5 choices each and remaining (10-4)= 6 questions have 4 choices each.
So, the possible sequences of answers for first 4 questions 
and the possible sequences of answers for remaining 6 questions 
Thus, the total possible number of sequences of answers = (625 × 4096) = 2560000
I assume that the given equation above is 0.9(x+1.4)−2.3+0.1x=1.6 and not 0.9(x+1.4)−2.3+0.1x=1.60.9(x+1.4)−2.3+0.1x=1.6, I think there is a typo error on this. Based on equation I assumed the answer is 2.64.Thank you for posting your question here, I hope my answer helps.
Answer:
35
Step-by-step explanation:
the pattern is +2 so the answer is 35
Let x = # of tickets sold in advance
Let y = # of tickets sold the day of
Cost of the tickets & total sales: 6x & 10y = 6828
You also know y = x + 206
Take the equation mentioned above y = x + 206 and sub it in anywhere the variable y is in the other equations so you'll have this:
6x + 10(x+206) = 6828
Now solve for x to get x = 298
To finish the problem, you must now find the number of y tickets sold.
Sub your x value that you found back into the equation y = x + 206 and you'll get y = 504.
So, 298 tickets were sold in advance and 504 tickets were sold the day of
F(x) = 2x² + 7x - 5
g(x) = -8x² - 3x + 5
g(x) + f(x)
-8x² - 3x + 5 + 2x² + 7x - 5
-8x² + 2x² - 3x + 7x + 5 - 5
-6x² + 4x + 0
-2x(3x - 2)
