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4 years ago

How many solutions does the linear system 3×+5y=8 and 3×+5y=1have

Mathematics

1 answer:

MrRa [10]4 years ago

3 0

Answer:

No solution

Step-by-step explanation:

When put in a graphing calculator, the lines are parallel and will never intersect, therefore there is no solution.

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4(x−1)−3(2x−5)<br> plz help

nikitadnepr [17]

First you distribute. 4 to x-1 and 3 times 2x-5 you should get 4x-4-6x+15 because -3 times -5 is positive 15. Combine like terms 6x-4x is 2x and 15-4 is 11

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3 years ago

Read 2 more answers

PLEASE ANSWER !

ivanzaharov [21]

Answer:I think no, because 25+35+45=150. 150x3=450

Maybe, for 4 months he'd have enough. So, 150x4=600. So Jamal would have some extra money!

Step-by-step explanation:

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4 years ago

Match each expression to its equivalent standard form.

Aleksandr [31]

Let's expand the products they are all in the form

$(a+b)(a-b)=a^2-b^2$

For the first one we have a=x and b=2i:

$(x+2i)(x-2i)=x^2-(2i)^2=x^2+4$

For the second one we have a=x-2 and b=2i:

$(x-2+2i)(x-2-2i)=(x-2)^2-(2i)^2 = x^2-4x+4+4=x^2-4x+8$

For the third one we have a=x+1 and b=i:

$(x+1+i)(x+1-i)=(x+1)^2-i^2=x^2+2x+1+1=x^2+2x+2$

3 0

4 years ago

A lottery ticket has a grand prize of $31 million. The probability of winning the grand prize is .000000018. Determine the expec

vlabodo [156]

Answer:

$0.558

Step-by-step explanation:

The expected value is the sum of the value of each outcome times the chance that it happens. In this case, there are two outcomes:

Win $31 million
Win $0

Then our expected value can be calculated as:

$EV=(31,000,000)(0.000000018)+(0)(1-0.000000018)=0.558$

5 0

3 years ago

Can you explain why in detail please?

Igoryamba

it would be the graph on the right.

Since the equation ends with +2 the line would be 2 above the x axis

4 0

3 years ago

How many solutions does the linear system 3×+5y=8 and 3×+5y=1have ​

How many solutions does the linear system 3×+5y=8 and 3×+5y=1have