All categories

3 years ago

Total 427 tickets sold 73 fewer student tickets than adult tickets how many adult tickets

Mathematics

1 answer:

viktelen [127]3 years ago

8 0

9514 1404 393

Answer:

250

Step-by-step explanation:

Let 'a' represent the number of adult tickets.

a +(a -73) = 427

2a = 500 . . . . . add 73

a = 250 . . . . . . divide by 2

250 adult tickets were sold.

_____

<em>Additional comment</em>

I call this a "sum and difference problem" because we are given the total of two values and the difference between them. As you can see here, the larger of the two values is the average of the given numbers, their sum divided by 2. This is the generic solution to such a problem: the larger number is the average of the given sum and difference.

You might be interested in

Write a pair of numbers such that the value of the 7 in the first number is 1,000 times the value of the 7 in the second number,

kirill [66]

437,000
400,307
In the second number, the 7 is moved 3 places to the right, and the 3 is moved 2 places to the right.

(The digit 4 is used here simply to make the numbers be the same overall length. It can be changed to any other digit (except 3 or 7) or removed. Digits that are not 3 or 7 can replace any of the zeros.)

8 0

3 years ago

PLEASE PLEASE PLEASE HELP ME ANSWER THIS QUESTION QUICK!! The picture of the question is down below.

d1i1m1o1n [39]

Answer:

A b c d

Step-by-step explanation:

pertaining to or using a rule or procedure that can be applied repeatedly. Mathematics, Computers. pertaining to or using the mathematical process of recursion: a recursive function; a recursive procedure.

4 0

3 years ago

Joshua created the following sequence. This sequence grows at a constant rate. Fill in the blanks with the missing terms of the

quester [9]

Answer: A is 32.5

B is 162.5

Step-by-step explanation:

so what i did was that i divided 65/13 and i got 5 and then i divided 5/2 and got 2.5 and then i multiplied 13 and 2.5 and got 32.5 and then i divided 32.5 and 2.5 and got 65 and then i multiplied 65 and 2.5 and got 162.5

hope that helped!

good luck :)

4 0

2 years ago

Read 2 more answers

Determine which of the sets of vectors is linearly independent. A: The set where p1(t) = 1, p2(t) = t2, p3(t) = 3 + 3t B: The se

defon

Answer:

The set of vectors A and C are linearly independent.

Step-by-step explanation:

A set of vector is linearly independent if and only if the linear combination of these vector can only be equalised to zero only if all coefficients are zeroes. Let is evaluate each set algraically:

$p_{1}(t) = 1$ , $p_{2}(t)= t^{2}$ and $p_{3}(t) = 3 + 3\cdot t$ :

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (3 +3\cdot t) = 0$

$(\alpha_{1}+3\cdot \alpha_{3})\cdot 1 + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot t = 0$

The following system of linear equations is obtained:

$\alpha_{1} + 3\cdot \alpha_{3} = 0$

$\alpha_{2} = 0$

$\alpha_{3} = 0$

Whose solution is $\alpha_{1} = \alpha_{2} = \alpha_{3} = 0$ , which means that the set of vectors is linearly independent.

$p_{1}(t) = t$ , $p_{2}(t) = t^{2}$ and $p_{3}(t) = 2\cdot t + 3\cdot t^{2}$

$\alpha_{1}\cdot p_{1}(t) + \alpha_{2}\cdot p_{2}(t) + \alpha_{3}\cdot p_{3}(t) = 0$

$\alpha_{1}\cdot t + \alpha_{2}\cdot t^{2} + \alpha_{3}\cdot (2\cdot t + 3\cdot t^{2})=0$

$(\alpha_{1}+2\cdot \alpha_{3})\cdot t + (\alpha_{2}+3\cdot \alpha_{3})\cdot t^{2} = 0$

The following system of linear equations is obtained:

$\alpha_{1}+2\cdot \alpha_{3} = 0$

$\alpha_{2}+3\cdot \alpha_{3} = 0$

Since the number of variables is greater than the number of equations, let suppose that $\alpha_{3} = k$ , where $k\in\mathbb{R}$ . Then, the following relationships are consequently found: