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Brut [27]
3 years ago
15

Solve the system of equations.

Mathematics
2 answers:
Sloan [31]3 years ago
7 0

Answer:

b.

( -3, -5)

Step-by-step explanation:

6x + 13 = 2x + 1

6x -2x = 1-13

4x = -12

x = -12/4 = -3

y = 6x + 13

y = 6(-3) +13 = -18+13 = -5

(x, y) = (-3,-5)

Nat2105 [25]3 years ago
7 0
Y=y therefore,
6x+13=2x+1
6x-2x=1-13
4x= -12
x= -12/4
x= -3

y=6(-3) +13
y= -18+13
y= -5
(x,y)=(-3,-5)
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Pls help this is important ty <3
Gnoma [55]
Graph it on the bottom 4
8 0
2 years ago
part b is: if the energy release of one earthquake is 10,000 times that of another, how much larger is the Richter scale reading
kotegsom [21]

You could use the information from part A to get B. I'm not sure if you want A or not, so I'll do it as well.

A

Eo = 10^4.4 Joules

E = 2 * 10^15

Formula

M = (2/3) log (E/Eo)

M = 2/3 * log (2 * 10^15/10^(4.4) )

M = 2/3 * log( 7.9621* 10^10)

M = 2/3 * 10.901

M = 7.26735 on the Richter scale. That is a huge amount of energy.

Part B

Suppose that you use Eo and your base. Eo is 10^4.4

Now the new earthquake is E = 10000 * Eo

So what you get now is M = (2/3)* Log(10000 * Eo / Eo )

The Eo's cancel out.

M = 2/3 * log(10000)

M = 2/3 of 4

M = 8/3

M = 2.6667 difference in the Richter Scale Reading. It is still an awful lot of energy.

What this tells you is that if the original reading was (say) 6 then the 10000 times bigger reading would 8.266667

Answer: M = 2.6667


8 0
3 years ago
Read 2 more answers
Dorian buys 2 pounds of almonds for $21.98 and 3 pounds of dried apricots for $26.25. Which is less expensive per pound? how muc
Bogdan [553]
Apricots is 8.75 per pound and is less expensive than almonds per pound (10.99). To find how much less expensive you subtract apricots from almonds. 10.99-8.75= 2.24.

Please vote my answer brainliest. thanks!
7 0
3 years ago
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What is 0.216 (26 recurring) as a fraction?
ankoles [38]
216/1000

Simplify it by 2

Give me a thanks if it helps!!!
8 0
4 years ago
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The odds against Carl beating his friend in a round of golf are 9:7. Find the probability that Carl will lose?
grandymaker [24]

The ratio 9:7 gives you following statement:

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Then the probability that Carl will lose is

Pr(\text{Carl will lose})=\dfrac{7}{16}.

Answer: Pr(\text{Carl will lose})=\dfrac{7}{16}.


7 0
3 years ago
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