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snow_lady [41]
3 years ago
6

Two elephants are being delivered to the zoo. One elephant weighs 23,453 pounds, and the other elephant weighs 19,916 pounds.

Mathematics
2 answers:
Naily [24]3 years ago
6 0

Answer:

D

Step-by-step explanation:

Marizza181 [45]3 years ago
5 0
I believe the answer to this question is D
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You have a ribbon that is 6 7/8 inches long. You use 2/5 of it on a project. How much ribbon is left?
weqwewe [10]

Answer:

Oof

Step-by-step explanation:idk sorry

8 0
3 years ago
Read 2 more answers
A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d
bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

  • Sample size n > 30
  • Sample mean = \overline{x}
  • Sample standard deviation = s
  • Population standard deviation = \sigma
  • Level of significance = \alpha

Then the confidence interval is obtained as

  • Case 1: Population standard deviation is known

\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}

  • Case 2: Population standard deviation is unknown.

\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}

For this case, we're given that:

  • Sample size n = 90 > 30
  • Sample mean = \overline{x} = 138
  • Sample standard deviation = s = 34
  • Level of significance = \alpha = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: Z_{0.1/2} = ±1.645

Thus, we get:

CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C:  [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

3 0
2 years ago
Use the formula for compound amount:$14,800 at 6% compounded semiannually for 4 years
GalinKa [24]

SOLUTION

Given the question in the question tab, the following are the solution steps to answer the question.

STEP 1: Write the formula for calculating compound amount

A=P(1+\frac{r}{n})^{nt}

where

A = final compounded amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

STEP 2: Write the given data

Semiannually means that n will be 2

P=14,800,r=\frac{6}{100}=0.06,n=2,t=4

STEP 3: Calculate the compound amount

\begin{gathered} A=14800(1+\frac{0.06}{2})^{2\times4}\Rightarrow A=14800(1+0.03)^{2\times4} \\ A=14800(1.03)^8 \\ A=14800\times1.266770081 \\ A=\text{\$}18,748.1972 \end{gathered}

Hence, the compounded amount after 4 years is $18,748.1972

6 0
1 year ago
What is the answer 2x5-5=
coldgirl [10]
The answer to that question is 5
4 0
2 years ago
work out the total area of triangle ABC. calculate the area of AC. sides are:8.2cm and 13.5cm and angle 81 degrees
umka2103 [35]

Answer:

54.67 cm²

Step-by-step explanation:

Given that the two sides of Δ ABC are 8.2 cm and 13.5 cm and the angle included by those sides is 81°.

Let, b = 8.2 cm and c = 13.5 cm and ∠ A = 81°

Hence, area of triangle ABC, Δ = \frac{1}{2} bc \sin A

⇒ Δ = \frac{1}{2} bc \sin 81

⇒ Δ = \frac{8.2 \times 13.5 \times \sin 81}{2}

⇒ Δ = 54.67 cm² (Answer)

7 0
3 years ago
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