Answer:
A=8.75 in.
Step-by-step explanation:
Since ∆ HBA & ∆HKJ are similar,
HB/HA = HK/HJ
3/5.25 = 8/HJ
3HJ/5.25 = 8
3HJ = 42
HJ = 14 in.
AJ = 14 - 5.25
AJ = 8.75 in.
Therefore
A=8.75 in.
I hope this helped you.
Answer:

Step-by-step explanation:

Answer:
5 1/3 mph or 5.33mph
Step-by-step explanation:
1/3 of a mile / 1/16 of an hour = MPH. In order to divide fractions you flip the bottom fraction and multiply across. 1/3 / 1/16 = 1/3 * 16/1 = 16/3 = 5 1/3 = 5.33mph
Answer:
(a)18
(b)1089
(c)Sunday
Step-by-step explanation:
The problem presented is an arithmetic sequence where:
- First Sunday, a=1
- Common Difference (Every subsequent Sunday), d=7
We want to determine the number of Sundays in the 120 days before Christmas.
(a)In an arithmetic sequence:

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.
Therefore, Aldsworth advertised 18 times.
(b)Next, we want to determine the sum of the first 18 terms of the sequence
1,8,15,...

The sum of the numbers of days published in all the advertisements is 1089.
(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.
The population of the town from 2000 to 2020 is modeled by the equation:

Where t is the number of years since 2000.
We have to find the expected population of the town in 2002. The number of years from 2000 to 2002 are 2, so we have to find p(2). Replacing t by 2 in the above equation, we get:
So, according to the model, the population of town in 2002 is predicted to be 11,025.