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snow_lady [41]
3 years ago
6

Two elephants are being delivered to the zoo. One elephant weighs 23,453 pounds, and the other elephant weighs 19,916 pounds.

Mathematics
2 answers:
Naily [24]3 years ago
6 0

Answer:

D

Step-by-step explanation:

Marizza181 [45]3 years ago
5 0
I believe the answer to this question is D
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What is the length of if ?<br><br> 8 in.<br> 8.75 in.<br> 10.25 in.<br> 14 in.
Ket [755]

Answer:

A=8.75 in.

Step-by-step explanation:

Since ∆ HBA & ∆HKJ are similar,  

HB/HA = HK/HJ  

3/5.25 = 8/HJ  

3HJ/5.25 = 8  

3HJ = 42  

HJ = 14 in.

AJ = 14 - 5.25  

AJ = 8.75 in.

Therefore

A=8.75 in.

I hope this helped you.

5 0
4 years ago
Read 2 more answers
What is the slope of the line that passes through the two given points? (13, -2) and (3, -2)
Zolol [24]

Answer:

the \: slope \: is \:  \boxed{0}

Step-by-step explanation:

the \: slope \:  : m = \frac{  - 2 - ( - 2)}{3 - 13}  = -   \frac{0}{10}

5 0
3 years ago
Mansa runs 1/3 of a mile in 1/16 of an hour. what is his unit rate in miles per hour​
REY [17]

Answer:

5 1/3 mph or 5.33mph

Step-by-step explanation:

1/3 of a mile / 1/16 of an hour = MPH. In order to divide fractions you flip the bottom fraction and multiply across. 1/3 / 1/16 = 1/3 * 16/1 = 16/3 = 5 1/3 = 5.33mph

5 0
3 years ago
One Sunday, 120 days before Christmas, Aldsworth store publishes an advertisement saying ‘120 shopping days until Christmas'. Al
Lena [83]

Answer:

(a)18

(b)1089

(c)Sunday

Step-by-step explanation:

The problem presented is an arithmetic sequence where:

  • First Sunday, a=1
  • Common Difference (Every subsequent Sunday), d=7

We want to determine the number of Sundays in the 120 days before Christmas.

(a)In an arithmetic sequence:

\text{The nth term}, T_n=a+(n-1)d\\T_n \leq 120\\$Therefore:$\\1+7(n-1) \leq 120\\1+7n-7\leq 120\\7n-6\leq 120\\7n\leq 120+6\\7n\leq 126\\$Divide both sides by 7$\\n\leq 18

Since the result is a whole number, there are 18 Sundays in which Aldsworth advertises.

Therefore, Aldsworth advertised 18 times.

(b)Next, we want to determine the sum of the first 18 terms of the sequence

1,8,15,...

\text{Sum of a sequence}, S_n=\frac{n}{2}( 2a+(n-1)d)\\S_{18}=\frac{18}{2}( 2*1+(18-1)*7)\\=9(2+17*7)\\=9(2+119)\\=9*121\\S_{18}=1089

The sum of the numbers of days published in all the advertisements is 1089.

(c)SInce the 120th day is the 18th Sunday, Christmas is on Sunday.

6 0
3 years ago
The population of a certain town was 10,000 in the year 2000 the town manager predicted that for the next 20 years the populatio
Bond [772]
The population of the town from 2000 to 2020 is modeled by the equation:

p(t)=10000(1.05)^{t}

Where t is the number of years since 2000.

We have to find the expected population of the town in 2002. The number of years from 2000 to 2002 are 2, so we have to find p(2). Replacing t by 2 in the above equation, we get:

p(2)=10000(1.05)^{2}  \\  \\ &#10;p(2)=11025

So, according to the model, the population of town in 2002 is predicted to be 11,025.
8 0
3 years ago
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