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Lorico [155]
3 years ago
14

A square is shown below. Which expression can be used to find the area, in square units, of the shaded triangle in the square?

Fraction 1 over 4 • 6•6 Fraction 1 over 2 •3•3
Fraction 1 over 4 •3•3
Fraction 1 over 2 •6•6

Mathematics
2 answers:
ELEN [110]3 years ago
7 0

Answer:

Area = \frac{1}{2} (6)(6)

Step-by-step explanation:

Area of Triangle = \frac{1}{2} (Base)(Height)

Where Base = 6 , Height = 6

Area = \frac{1}{2} (6)(6)

Area = 3 * 6

<u><em>Area = 18 units^2</em></u>

kotegsom [21]3 years ago
6 0

Answer:

Hey there!

The area of the shaded triangle covers exactly half the square.

Thus, first we find the area of the square, which is 6x6, or 36.

Finally, half of that is 1/4 times 6x6.(Fraction 1 over 2 •6•6 is correct)

Let me know if you need more help :)

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John runs a computer software store. Yesterday he counted 123 people who walked by the store, 56 of whom came into the store. Of
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Answer:

a) There is a 45.53% probability that a person who walks by the store will enter the store.

b) There is a 41.07% probability that a person who walks into the store will buy something.

c) There is a 18.70% probability that a person who walks by the store will come in and buy something.

d) There is a 58.93% probability that a person who comes into the store will buy nothing.

Step-by-step explanation:

This a probability problem.

The probability formula is given by:

P = \frac{D}{T}

In which P is the probability, D is the number of desired outcomes and T is the number of total outcomes.

The problem states that:

123 people walked by the store.

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(a) Estimate the probability that a person who walks by the store will enter the store.

123 people walked by the store and 56 entered the store, so T = 123, D = 56.

So

P = \frac{D}{T} = \frac{56}{123} = 0.4553

There is a 45.53% probability that a person who walks by the store will enter the store.

(b) Estimate the probability that a person who walks into the store will buy something.

56 people came into the store and 23 bought something, so T = 56, D = 23.

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P = \frac{D}{T} = \frac{23}{56} = 0.4107

There is a 41.07% probability that a person who walks into the store will buy something.

(c) Estimate the probability that a person who walks by the store will come in and buy something.

123 people walked by the store and 23 came in and bought something, so T = 123, D = 23.

So

P = \frac{D}{T} = \frac{23}{123} = 0.1870

There is a 18.70% probability that a person who walks by the store will come in and buy something.

(d) Estimate the probability that a person who comes into the store will buy nothing.

Of the 56 people whom came into the store, 23 bought something. This means that 56-23 = 33 of them did not buy anything. So:

D = 33, T = 56

P = \frac{D}{T} = \frac{33}{56} = 0.5893

There is a 58.93% probability that a person who comes into the store will buy nothing.

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