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VikaD [51]
3 years ago
7

your standing 12 feet in front of a building. The angle of elevation to the top of the building is 76 degrees. How tall is the b

uilding?
Mathematics
1 answer:
Oksanka [162]3 years ago
6 0

TAN(76°) = x/12 --> x = 48.13 feet

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A honeybee flaps its wings 200 times per second.how much time is required for one wingbeat? give your answere in millisecond
Fiesta28 [93]

The time required for one wing beat is 5 milliseconds.

<em><u>Explanation</u></em>

Lets assume, the time required for one wing beat is  t seconds

So, the time required for 200 wing beat = 200t seconds

Given that, the honeybee flaps its wings 200 times per 1 second. So...

200t=1 \\ \\ t=\frac{1}{200}seconds\\ \\ t= (\frac{1}{200}*1000 )milliseconds\\ \\ t=( 5 )milliseconds

So, the time required for one wing beat is 5 milliseconds.

7 0
3 years ago
How to simplify 20/10
Andreyy89

In order to get the answer to this question you will have to find the common factor and then divide the numerator and denominator by the common factor to get the answer.

\frac{20}{10}

CF=10

20\div10=2

10\div10=1

\frac{2}{1} =2

= \frac{2}{1} or2

Therefore the answer is "2."

Hope this helps.

4 0
3 years ago
What is the simplified version of 3\sqrt{135}
Aleonysh [2.5K]

Answer:

The simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

Step-by-step explanation:

The given expression is

\sqrt[3]{135}

According to the property of radical expression.

\sqrt[n]{x}=(x)^{\frac{1}{n}}

Using this property we get

\sqrt[3]{135}=(135)^{\frac{1}{3}}

\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3)^{\frac{1}{3}}\times (5)^{\frac{1}{3}}      [\because (ab)^x=a^xb^x]

\sqrt[3]{135}=3\times \sqrt[3]{5}     [\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]

\sqrt[3]{135}=3\sqrt[3]{5}

Therefore the simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

7 0
3 years ago
Read 2 more answers
Prove algebraically that r = 10/2+2sinTheta is a parabola
Xelga [282]

Answer:

y =  -  \frac{ 1 }{10} {x}^{2}   +  \frac{5}{2}

Step-by-step explanation:

We want to prove algebraically that:

r =  \frac{10}{2 + 2 \sin \theta}

is a parabola.

We use the relations

{r}^{2}  =  {x}^{2}  +  {y}^{2}

and

y = r \sin \theta

Before we substitute, let us rewrite the equation to get:

r(2 + 2 \sin \theta) = 10

Or

r(1+  \sin \theta) = 5

Expand :

r+  r\sin \theta= 5

We now substitute to get:

\sqrt{ {x}^{2}  +  {y}^{2} }  + y = 5

This means that:

\sqrt{ {x}^{2}  +  {y}^{2} }=5 - y

Square:

{x}^{2}  +  {y}^{2} =(5 - y)^{2}

Expand:

{x}^{2}  +  {y}^{2} =25 - 10y +  {y}^{2}

{x}^{2}  =25 - 10y

{x}^{2}  - 25 =  - 10y

y =  -  \frac{ {x}^{2} }{10}  +  \frac{5}{2}

This is a parabola (0,2.5) and turns upside down.

4 0
3 years ago
How do you convert 4.5 hours to minutes ?
marta [7]
Multiply the number of minutes in an hour(60) by 4.5
7 0
2 years ago
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