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kozerog [31]
3 years ago
5

Find the measure of the arc indicated by a "?."

Mathematics
2 answers:
nika2105 [10]3 years ago
7 0

Answer:

55o

Step-by-step explanation:

gregori [183]3 years ago
4 0
What does the measure look like
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Which table represent a linear function
andrew-mc [135]
The first one it goes up in the same increments
8 0
3 years ago
X+1<br> -<br> and h(x) = 4 - X, what is the value<br> Oil CD<br> Nior<br> wla<br> olo
timofeeve [1]

Answer:

8/5

Step-by-step explanation:

(g\circ h)(-3) means g(h(-3)).

Start with the inside first: h(-3).

h(-3) means use the function called h and replace the x with -3.  The expression that is called h is 4-x.

4-x evaluated at x=-3 gives us 4-(-3)=4+3=7.

So the value for h(-3) is 7, or h(-3)=7.

Now this is what we thus far:

(g\circ h)(-3)=g(h(-3))=g(7).

g(7) means use the function called g and replace x with 7.   The expression that is called g is (x+1)/(x-2).

(x+1)/(x-2) evaluated at x=7 gives us (7+1)/(7-2)=(8)/(5)=8/5.

This is our final answer:

(g\circ h)(-3)=g(h(-3))=g(7)=\frac{8}{5}.

7 0
3 years ago
Choose any method to find the gcf of 40 16 and 24
Juli2301 [7.4K]

The GCF of 40 16 and 24 is 8

<h3>How to determine the GCF of 40 16 and 24?</h3>

The numbers are given as:

40 16 and 24

Start by listing out the factors of the numbers:

This is done as follows:

  • The factors of 40 are: 1, 2, 4, 5, 8, 10, 20, 40
  • The factors of 16 are: 1, 2, 4, 8, 16
  • The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24

Then the greatest common factor in the above list is 8.

Hence, the GCF of 40 16 and 24 is 8

Read more about GCF at:

brainly.com/question/219464

#SPJ1

8 0
2 years ago
Find the distance from P to l.
ki77a [65]
Equation\ of\ a\ line\ from\ 2\ points (x_1;\ y_1);\ (x_2;\ y_2):\\\\y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)\\\\(-4;\ 2)\ and\ (3;-5)\\subtitute:\\\\y-2=\dfrac{-5-2}{3-(-4)}\cdot(x-(-4))\\\\y-2=\dfrac{-7}{7}\cdot(x+4)\\\\y-2=-(x+4)\\\\y-2=-x-4\ \ \ |add\ x\ and\ 4\ to\ both\ sides\\\\x+y+2=0\\-------------------\\

Point-line\ distance\\l:Ax+By+C=0;\ (x_0;\ y_0)\\\\d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+B^2}}\\\\x+y+2=0\to A=1;\ B=1;\ C=2\\(1;\ 2)\to x_0=1;\ y_0=2\\subtitute\\\\d=\dfrac{|1\cdot1+1\cdot2+2|}{\sqrt{1^2+1^2}}=\dfrac{|1+2+2|}{\sqrt2}=\dfrac{|5|}{\sqrt2}=\dfrac{5}{\sqrt2}=\dfrac{5\cdot\sqrt2}{\sqrt2\cdot\sqrt2}\\\\=\boxed{\dfrac{5\sqrt2}{2}}
4 0
3 years ago
Whats 87 + 72 tenths
Alchen [17]

Answer:

94.2

Step-by-step explanation:

google and simple addition

8 0
3 years ago
Read 2 more answers
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