Answer:
The area is about 153.938
Step-by-step explanation:
To find the area of a circle, you have the equation
πr squared
the diameter is 14, so the radius is 7.
pi 7 squared is equal to about 153.938
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Answer:
(2.5 , 3.5)
Step-by-step explanation:
We can use the midpoint formula . Here the points are , (2,2) and (3,5) .
• <u>Using</u><u> </u><u>Midpo</u><u>int</u><u> Formula</u><u> </u><u>:</u><u>-</u><u> </u>
⇒ M = { (x1 + x2)/2 , (y1 + y2)/2 }
⇒ M = ( 2+3/2 , 5+2/2 )
⇒ M = ( 5/2 , 7/2 )
⇒ M = ( 2.5 , 3.5 )
<h3>
<u>Hence </u><u>the</u><u> </u><u>midpoint</u><u> </u><u>is</u><u> </u><u>(</u><u>2</u><u>.</u><u>5</u><u> </u><u>,</u><u> </u><u>3</u><u>.</u><u>5</u><u>)</u></h3>
Answer: Δx = 0.5
Step-by-step explanation:
We have the interval:
[−3, −1]
and we partition it into 4 equal intervals.
first, the range of our interval is equal to the difference between the extremes, this is:
-1 - (-3) = -1 + 3 = 2
Then, if we divide it into 4, we have 4 segments with a range of:
2/4 = 0.5
Then the subinterval delta is 0.5, and the 4 intervals are:
[−3, -2.5], [−2.5, −2], [−2, −1.5], [−1.5, −1]
Answer:
The given equation having only one solution i.e., "w = 3". A further explanation is provided below.
Step-by-step explanation:
The given equation is:
⇒ 
By opening the brackets, we get
⇒ 
⇒ 
On adding "83" both sides, we get
⇒ 
⇒ 
⇒ 
⇒ 
Answer:
<h2>In this particular case,the target population of interest to the university administration constitutes the university students.</h2>
Step-by-step explanation:
- The university administration is interested to conduct a statistical study to identify the average or mean time taken by the students to find a vacant parking spot.
- Therefore,the research topic here is the average time taken by the university students to find parking spot. The administrator collects an inconspicuous sample of 240 samples from the target population of the study,which is the overall student population of the university.
- The sample collected by the university administration is used to observe the average or mean parking time by the university students.
