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tino4ka555 [31]
4 years ago
5

Solve H = 5as +10a for s.

Mathematics
1 answer:
GaryK [48]4 years ago
7 0

Answer:

s = (H/a - 10)/5

Step-by-step explanation:

H = 5as +10a

H = a(5s +10)

H/a = 5s +10

H/a - 10 = 5s

(H/a - 10)/5 = s

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I need help with slope ​
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Answer:

Step-by-step explanation:

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8 0
4 years ago
A chemist is using 362 milliliters of a solution of acid and water. If 12.1% of the solution is acid, how many milliliters of ac
PSYCHO15rus [73]

Answer:

The answer to your question is 43.8 mL of acid.

Step-by-step explanation:

Data

Total volume = 362 ml

12.1 % is acid

The Volume of acid = ?

Process

1.- Use the rule of three and cross multiplication to solve this problem.

               362 ml ------------------- 100%

                    x       -------------------  12.1 %

                    x = (12.1 x 362) / 100

                    x = 4380.2 / 100

                    x = 43.802 ml

2.- Round your answer to the nearest tenth.

                        43.802   only consider the first decimal

                        43.8 mL

3.- Conclusion

    A 12.1% solution of acid has 43.8 mL of acid.

6 0
3 years ago
Read 2 more answers
What is the equation of the line perpendicular to the line y = 3x + 2 and passing through the point (3, -4)?
In-s [12.5K]

Answer:

Step-by-step explanation:

perp. -1/3

y + 4 = -1/3(x - 3)

y + 4 = -1/3x + 1

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4 0
3 years ago
In PQR, Q = 76, PQ = 18, and QR = 27<br> Can you help me with 5!
SashulF [63]

Answer:

The answer is

m<p =66°21'14"

m<R =37°38'46"

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Step-by-step explanation:

{pr}^{2}  =  {18}^{2}  +  {27}^{2}  - 2 \times 18 \times 27 \cos(76)  = 817.85 \\ pr = 28.6 \\  \cos(p)  =   \frac{ {18}^{2}  +  {28.6}^{2} -  { {27}^{2} }  }{2 \times 18 \times 28.6 } = 0.4 \\ m < p = 66.42 \\ m < r = 180 - 76 - 66.42 = 37.58

3 0
3 years ago
Erika found out that after working in her current job for 9 months she has earned 6 days of vacation
Arte-miy333 [17]

Answer:

4 days

Step-by-step explanation:

9 months/6 months = 6 days /x days

9/6 = 6/x

x = 4

6 0
3 years ago
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