All categories

3 years ago

Solve H = 5as +10a for s.

Mathematics

1 answer:

GaryK [48]3 years ago

7 0

Answer:

s = (H/a - 10)/5

Step-by-step explanation:

H = 5as +10a

H = a(5s +10)

H/a = 5s +10

H/a - 10 = 5s

(H/a - 10)/5 = s

You might be interested in

Please I really need help with this

romanna [79]

Answer:

A, 14

Step-by-step explanation:

Assuming that she has a total of d dollars, and spends half of it, then we have 1/2d. She then spends another 6 dollars, and therefore we would subtract. She is left with one dollar.

1/2d-6=1

Working backwards, we can solve for d, her total amount of money:

1/2d=7

d=14

I hope this helps! :)

6 0

3 years ago

5b +20y A. 5(b+4y) B. 5(4y+b) C. 2(b+10y)

enot [183]

Answer:

a once again it is easy the answer is A

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

HELPP my work is due soon plus i don’t understand :(

Mashcka [7]

Answer:

4. B

Step-by-step explanation:

8 0

3 years ago

3. A company with loud machinery needs to cut its sound intensity to 44% of its original level. By how many decibels would the l

sergeinik [125]

Answer: 3. The correct option is: A) 3.57 decibels.

6. The correct option is: B) $ln(\frac{x^2}{c^5})$ 

Step-by-step explanation:

3. Sound intensity is cut to 44% of its original level. That means, if the original sound intensity was 100, then now sound intensity will be 44.

So, $I_{0}= 100$ and $I= 44$

Using the formula $L= 10log(\frac{I}{I_{0}})$ , we will get.....

$L= 10log(\frac{44}{100})\\ \\ L= 10log(0.44)\\ \\ L= 10(-0.3565...)=-3.565...\approx -3.57$

(Rounded to the nearest hundredth)

So, the loudness would be reduced by 3.57 decibels.

6. Given expression is: $2ln(x) - 5ln(c)$

First applying the property $m*log(x)= log(x^m)$ , we will get.....

$ln(x^2)-ln(c^5)$

Now using the formula, $log(a)-log(b)= log(\frac{a}{b})$ , we will get....

$ln(x^2)-ln(c^5) = ln(\frac{x^2}{c^5})$

Thus, the answer as a single natural logarithm is $ln(\frac{x^2}{c^5})$

8 0

3 years ago

All I need is the equation plz and thank you

Vanyuwa [196]

Answer:

Number of photos = 3 * minutes

Step-by-step explanation:

7 0

3 years ago