Answer:
The side C equals to 10. hence the answer is letter A
Step-by-step explanation:
To solve this, we need to use trigonometric functions.
we know that sin (α) = Lo / H for a triangle. Being Lo : Length of the opposite side and H: Length of the hypotenuse.
Given α= 45º and Lo= 5√2 and replacing in the equation:
sin (45º) = 5√2 / C (1)
Using trigonometric identities we know that sin(45º) =(√2)/2. Replacing in equation (1):
sin (45º) = (√2)/2 = 5√2 / C ⇒ C = 2 *5 *√2 / (√2) ⇒ C=10
Since we need a point that divides K-->J into two segments in a 1:3 ratio, let's flip it to a 3:1 ratio in the J-->K direction. That means that this point is 3/(3+1) = 3/4 of the way up line JK.
Let's take 3/4 of the x of K (plus the 1 for the x of J):
3/4×(9 - 1) + 1 (because the beginning ofvthe line, at J, has an x of 1)...
3/4×(8) + 1 = 6 + 1 = 7
Therefore the answer is C) 7
1:4 400/100 and you get 1:4 ... there was 1 person at the second show for every 4 at the first
You find the eigenvalues of a matrix A by following these steps:
- Compute the matrix
, where I is the identity matrix (1s on the diagonal, 0s elsewhere) - Compute the determinant of A'
- Set the determinant of A' equal to zero and solve for lambda.
So, in this case, we have
![A = \left[\begin{array}{cc}1&-2\\-2&0\end{array}\right] \implies A'=\left[\begin{array}{cc}1&-2\\-2&0\end{array}\right]-\left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right]=\left[\begin{array}{cc}1-\lambda&-2\\-2&-\lambda\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-2%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D%20%5Cimplies%20A%27%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%26-2%5C%5C-2%260%5Cend%7Barray%7D%5Cright%5D-%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D%5Clambda%260%5C%5C0%26%5Clambda%5Cend%7Barray%7D%5Cright%5D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1-%5Clambda%26-2%5C%5C-2%26-%5Clambda%5Cend%7Barray%7D%5Cright%5D)
The determinant of this matrix is
Finally, we have
So, the two eigenvalues are
