The answer is: 10 x¹³ y¹⁰ .
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1x^8 * 2y^(10) * 5x^5 =
1* 2* 5 * x^8 * x^5 * y^(10) =
10 * x^(8+5) * y^(10) =
10 * x^(13) * y^(10) = 10 x^(13) y^10 ; write as:
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10 x¹³ y¹<span>⁰ .
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A direct variation equation is one that requires y varies directly as x and looks like this in equation form:

where k is the constant of variation. If we solve this for y, we have y = kx, which happens to be a linear function... a line. k here, then, serves as the slope. So what we are given as points on a direct variation function are actually points on a line. The equation for this requires that we find the slope and then rewrite the formula accordingly. First the slope:

Now we need to write the equation by using one of the points' coordinates. I picked the first point that has an x coordinate of -9 and a y coordinate of -3. Fitting those into the slope-intercept form of a line,

which simplifies to
-3 = -3 + b and b = 0. That means that the equation of direct variation is
or just

divide the temperature by the number of hours
36/12
answer: 3 degrees
Answer:
<NKM = 77⁰.
Step-by-step explanation:
< KMN = 1/2 * 116 = 58⁰
<JNK = <KMN = 58⁰
Consider the quadrilateral JKMN:
<NJK = 360 - 103 - 58 - 122 = 77⁰
So < JKN = 180 - 58 - 77 = 45⁰.
<NKM = 122-45 = 77⁰.