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3 years ago

When vehicles meet on a steep, narrow road, not wide enough for two vehicles, which vehicle must yield the right-of-way?

Physics

2 answers:

GaryK [48]3 years ago

6 0

Answer: B. The vehicle going downhill

Explanation: The vehicle going huphill needs more force to move, while the vehicle moving downhill actually can be moved only by the gravity acceleration.

So when both cars meet, if the car going uphill loses momentum, the vehicle may not be capable to keep moving uphill after that, so is better that the car going downhill yields the right-of-way to the other car, that needs to preserve the momentum.

Mkey [24]3 years ago

4 0

<span>When vehicles meet on a steep, narrow road which isnot wide enough for two vehicles, the vehicle going downhill must yield the right-of-way by backing up to a wider place or by stopping to leave sufficient space for the vehicle going uphill, except where it is more practical for the vehicle going uphill </span>

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A piece of wood has a mass of 8g and a volume of 10cm³ work out the density of the wood

olchik [2.2K]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 8 g

volume = 10 cm³

We have

$density = \frac{8}{10} = \frac{4}{5} = 0.8 \\$

We have the final answer as

Hope this helps you

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3 years ago

How fast is a skydiver going after 5 seconds or free fall and how far did he fall

RSB [31]

i'm just saying that this question makes no sense to me....but thanks for the points UwU

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3 years ago

Read 2 more answers

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gizmo_the_mogwai [7]

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4 years ago

Consider a ship of mass 2 x 10^6 kg with propeller blades of radius 7 m and it can push water backwards to a speed of 2 m/s. Giv

PolarNik [594]

Answer:

$a = 0.308 m/s^2$

Explanation:

As we know that the force due to propeller when it will push the water backwards is given as

$F = \frac{dP}{dt}$

now we know that

$P = mv$

so we have

$F = v\frac{dm}{dt}$

$F = v \rhoA\frac{dx}{dt}$

$F = \rho A v^2$

here we know that

$A = \pi r^2$

$A = \pi(7^2)$

$A = 154 m^2$

now the force is given as

$F = (1000)(154)(2^2)$

$F = 616000 N$

now the acceleration of the ship is given by Newton's II law

$a = \frac{F}{m}$

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3 0

3 years ago

Thwo charges, -10 nc and -10 nc are 1.0 cm apart on the x-axis. what is the total electric

expeople1 [14]

The electrostatic force is 9 x 10¯³ N.

We need to know about electrostatic force to solve this problem. The electrostatic force is applied on a charge which has near position to another charge. It can be determined by

F = k Q1 . Q2 / r²

where F is electrostatic force, k is Coulomb constant (9 x 10⁹ Nm²/C²), Q1 and Q2 are the charges and r is the radius or distance between the charges.

From the question above, we know that

Q1 = -10 nC = -10 x 10¯⁹ C

Q2 = -10 nC = -10 x 10¯⁹ C

r = 1 cm = 0.01 m

By substituting the following parameters, we can calculate the electrostatic force

F = k Q1 . Q2 / r²

F = (9 x 10⁹ . 10 x 10¯⁹ . 10 x 10¯⁹ / (0.01)²

F = 9 x 10¯³ N

Hence, the electrostatic force is 9 x 10¯³ N.

Find more on electrostatic force at: brainly.com/question/17692887

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2 years ago