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Leokris [45]
3 years ago
5

Do part b please if you have a question just text me

Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
8 0
1 is the body cell and 2 is the gamete. he reason is because the 1st one consists of more chromosomes than the second. a gamete will only consist of 23 while a body cell will consist of 46
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At what wavelength would a star radiate the greatest amount of energy if the star has a surface temperature of 60,000 K?
kompoz [17]

Answer:

\lambda=4.81\times 10^{-8}\ m

Explanation:

We have,

The surface temperature of the star is 60,000 K

It is required to find the wavelength of a star that radiated greatest amount of energy. Wein's displacement law gives the relation between wavelength and temperature such that :

\lambda T=2.89\times 10^{-3}

Here,

\lambda = wavelength

\lambda=\dfrac{2.89\times 10^{-3}}{60000}\\\\\lambda=4.81\times 10^{-8}\ m

So, the wavelength of the star is 4.81\times 10^{-8}\ m.

7 0
3 years ago
Is the star moving toward earth, away from earth, or is there not enough information provided to determine its motion?
ivanzaharov [21]

If a star is moving towards Earth, shift towards the blue end of the spectrum, this is called blue shift. If the star is moving away from Earth the light from that star will be red and is called red shift .

The faster a star moves towards the earth, the more its light is shifted to higher frequencies. In contrast, if a star is moving away from the earth, its light is shifted to lower frequencies on the color spectrum

if a star is moving towards Earth, it appears to emit light that is shorter in wavelength compared to a source of light that isn't moving. Because shorter wavelengths correspond to a shift towards the blue end of the spectrum, this is called blue shift.

If the star is moving away from Earth, its light will lose energy to reach Earth, therefore the light from that star will be red and is called red shift

learn more about blue shift :

brainly.com/question/5368237?referrer=searchResults

#SPJ4

8 0
2 years ago
What do you mean by the mechanical advantage of a leaver is 4.​
Illusion [34]

Answer:

Explanation:

It means that you only need apply 1/4th of the actual force required to operate the lever as you have an mechanical advantage which permits you to do 4 times the work with the same amount of effort.

7 0
2 years ago
Read 2 more answers
A particular coaxial cable is comprised of inner and outer conductors having radii 1 mm and 3 mm respectively, separated by air.
noname [10]

Answer:

The value is  \rho_s  =  4.026 *10^{-6} \  C/m^2

Explanation:

From the question we are told that

   The radius of the inner conductor  is  r_1 = 1 \ mm =  0.001 \ m

    The radius of the outer conductor is  r_2 = 3 \ mm = 0.003 \  m

    The potential at the outer conductor is  V = 1.5 kV  =  1.5 *10^{3} \  V

Generally the capacitance per length of the capacitor like set up of the two conductors is

      C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}

Here \epsilon_o is the permitivity of free space with value  \epsilon_o =  8.85*10^{-12} C/(V \cdot m)

=>   C= \frac{2 *  3.142  * 8.85*10^{-12}  }{ ln [\frac{0.003}{0.001} ]}

=>   C= 50.6 *10^{-12} \  F/m

Generally given that the potential  of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge

Generally the line  charge density of the outer  conductor is mathematically represented as

      \rho_l  =  C *  V

=>   \rho_d  =  50.6*10^{-12} *  1.5*10^{3}

=>   \rho_d  =  7.59*10^{-8} \  C/m

Generally the surface charge density is mathematically represented as

        \rho_s  =  \frac{\rho_l }{2 \pi * r_2 }    here 2 \pi r = (circumference \ of \ outer \  conductor  )

=>    \rho_s  =  \frac{7.59 *10^{-8} }{2* 3.142 * 0.003 }

=>    \rho_s  =  4.026 *10^{-6} \  C/m^2

3 0
2 years ago
For lunch you and your friends decide to stop at the nearest deli and have a sandwich made fresh for you with 0.300 kg of Italia
Oliga [24]

Answer with Explanation:

We are given that

m_1=0.3 kg

m_2=0.4 kg

Spring constant,k=200 N/m

h=0.250 m

a.Speed of ham before collision

u=\sqrt{2gh}=\sqrt{2\times 9.8\times 0.25}=2.2m/s

Collision is inelastic

According to law of conservation of momentum

m_1u_1=(m_1+m_2)v

0.3\times 2.2=(0.3+0.4)v

v=\frac{0.3\times 2.2}{0.7}=0.94 m/s

Kinetic energy of masses=Spring potential energy at maximum distance

\frac{1}{2}(m_1+m_2)v^2=\frac{1}{2}kA^2

A^2=\frac{(m_1+m_2)v^2}{k}

A=\sqrt{\frac{(m_1+m_2)v^2}{k}}

Substitute the values

A=\sqrt{\frac{(0.3+0.4)\times (0.94)^2}{200}}=0.056 m=0.056\times 100=5.6 cm

1 m=100 cm

b.Time period,T=2\pi\sqrt{\frac{(m_1+m_2)}{k}}

T=2\pi\sqrt{\frac{(0.3+0.4)}{200}}=0.37 s

7 0
3 years ago
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