Question

Identify the effect of increasing acidity on the solubility of the given compounds Sr(OH)2 S r( O H) Subscript2 ZnS Z n S PbBr2 P b B r Subscript2 Ca3(PO4)2 C a Subscript3( P O Subscript4) Subscript2 NaI N a I BaCO3

Answer 1

Answer:

Solubilities of $Sr(OH)_{2},ZnS,Ca_{3}(PO_{4})_{2} and BaCO_{3}$ increases with increasing acidity

Explanation:

$Sr(OH)_{2}\rightleftharpoons Sr^{2+}+2 OH^{-}$

Concentration of $OH^{-}$ decreases with increasing acidity. Therefore solubility of $Sr(OH)_{2}$ increases to keep constant solubility product.

$ZnS\rightleftharpoons Zn^{2+}+S^{2-}$

Concentration of $S^{2-}$ decreases with increasing acidity due to formation of $H_{2}S$. therefore solubility of ZnS increases to keep constant solubility product

$PbBr_{2}\rightleftharpoons Pb^{2+}+2Br^{-}$

Increasing acidity have no effect on this above equilibrium. Therefore solubility of $PbBr_{2}$ remains constant.

$Ca_{3}(PO_{4})_{2}\rightleftharpoons 3Ca^{2+}+2PO_{4}^{3-}$

Concentration of $PO_{4}^{3-}$ decreases with increasing acidity due to formation of $H_{3}PO_{4}$. Therefore solubility of $Ca_{3}(PO_{4})_{2}$ increases to keep constant solubility product.

$NaI\rightleftharpoons Na^{+}+I^{-}$

Increasing acidity have no effect on this above equilibrium. Therefore solubility of NaI remains constant.

$BaCO_{3}\rightleftharpoons Ba^{2+}+CO_{3}^{2-}$

Concentration of $CO_{3}^{2-}$ decreases with increasing acidity due to formation of $H_{2}CO_{3}$. Therefore solubility of $BaCO_{3}$ increases to keep constant solubility product.