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salantis [7]
3 years ago
5

A graduated cylinder initially contained 11 mL of water and then an 8 g block of wood is put into it, changing the volume to 15

mL. What is the density of the wood?
Chemistry
1 answer:
Paul [167]3 years ago
8 0

Answer:

Density is 2

Explanation:

Do the final volume of water divided by the inital

volume of water to get 4

15-11 = 4

Volume = 2

Mass = 8

Then to the equation m/v

8/4 = 2

Density = 2

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Filtration can separate a mixture of fine sand and coarse gravel. The holes in the filter should be large enough to allow ______
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The sand to pass through, but not the gravel. Hope this helps!

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An electron that is in the highest energy level of an atom and determines the atom's chemical properties is called a(n)
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A chemistry student must write down in her lab notebook the concentration of a solution of sodium hydroxide. The concentration o
HACTEHA [7]

Answer:

1.099 gmL¯¹ ≈ 1.1 gmL¯¹

Explanation:

From the question given above, the following were obtained:

Mass of empty cylinder = 9.5 g

Mass Cylinder + NaOH = 31.92 g

Volume of solution = 20.4 mL

Concentration of solution =?

Next, we shall determine the mass of sodium hydroxide, NaOH. This can be obtained as as illustrated below:

Mass of empty cylinder = 9.5 g

Mass Cylinder + NaOH = 31.92 g

Mass of NaOH =?

Mass of NaOH = (Mass Cylinder + NaOH) – (Mass of empty cylinder)

Mass of NaOH = 31.92 – 9.5

Mass of NaOH = 22.42 g

Finally, we shall determine concentration of the solution as follow:

Mass of NaOH = 22.42 g

Volume of solution = 20.4 mL

Concentration of solution =?

Concentration = mass /volume

Concentration of solution = 22.42 / 20.4

Concentration of solution = 1.099 gmL¯¹ ≈ 1.1 gmL¯¹

Therefore, the concentration of the solution is 1.1 gmL¯¹

3 0
3 years ago
To balance a chemical equation it may be necessary to adjust the
Mars2501 [29]

Answer:

  • <em>To balance a chemical equation it may be necessary to adjust the </em><u>coefficients.</u>

Explanation:

The <em>coefficients</em> of a <em>chemical equation</em> are the numbers that you put in front of each reactant and product. They are used to balance the equation and comply with the law of mass conservation.

By adjusting the coefficients you obtain the relative amounts (moles) of each product and reactant, i.e. the mole ratios.

Here an example.

The first information is what is called a word equation. E.g. nitrogen and hydrogen react to form ammonia:

  • Word equation: hydrogen + nitrogen → ammonia

  • Skeleton equation: H₂ + N₂ → NH₃

        This equation shows the chemical formulae but it is not balanced. The law of mass conservation is not observed.

So, in order to comply with the law of mass conservation you adjust the coefficients as follow.

  • Balanced chemical equation: 3H₂ + N₂ → 2NH₃

        As you see, it was necessary to modify the coefficients. Now the law of conservation of mass is observed and you get the mole ratios:

  • 3 mol H₂ : 1 mol  N₂ : 2 mol NH₃

       

4 0
3 years ago
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