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defon
3 years ago
9

When you break an iron magnet into two pieces, you get ____.

Chemistry
2 answers:
Rudiy273 years ago
5 0

Answer:

two north poles and two south poles

Explanation:

A single magnet has a north pole and a south pole. If it is broken into two pieces, then each of the two pieces will have a north pole and a south pole.

No matter how many times or into how many pieces a magnet is broken, the resulting pieces will have two poles each.

Hatshy [7]3 years ago
3 0

Answer:

Each piece will still have a north pole and a south pole.

Explanation:

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IUPAC name <br> fast !! Important!
dmitriy555 [2]

Answer:

Arkham

Explanation:

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8 0
2 years ago
Substance being reduced?​
lana [24]

Answer:

Ni^{2+}

Explanation:

From the equation attached , Ni^{2+} is reduced. This is because reduction is equivalent to decrease in the oxidation number. In the equation , The oxidation number of Ni is reduced from +2 to 0.

NB, The oxidation number of a neutral atom is zero

4 0
4 years ago
How is it possible to have thousands of different proteins when there are only 20 different amino acids?
STatiana [176]
Hi there!

Although there are only 20 amino acids, these amino acids can combine into an innumerable amount of combinations to form different and unique proteins. 

In case that doesn't make sense to you, I'll provide you with an analogy. You could be provided with 20 different LEGO bricks to work with. While there may only be 20 bricks, these bricks can combine into a vast amount of different formations, structures, etc. Amino Acids work in the same way.
3 0
3 years ago
CHEM HELP ASAP!! <br><br> What mass of H2 would be needed to produce 208 kg of methanol?
Eddi Din [679]

So if we use the equation:

CO+2H_{2} → CH_{3}OH

We can then determine the amount of H_{2} needed to produce 208 kg of methanol.

So let's find out how many moles of methanol 208 kg is:

Methanol molar weight = 32.041g/mol

So then we can solve for moles of methanol:

208kg*\frac{1,000g}{1kg} *\frac{1mol}{32.041g} =6,491.68mol

So now that we have the amount of moles produced, we can use the molar ratio (from the balanced equation) of hydrogen and methanol. This ratio is 2:1 hydrogen:methanol.

Therefore, we can set up a proportion to solve for the moles of hydrogen needed:

\frac{2}{1} =\frac{x}{6,491.68}

x=12,983.36mol

So now that we have the number of moles of H_{2} that are produced, we can then use the molar weight of hydrogen to solve for the mass that is needed:

12,983.36mol*\frac{2.016g}{1mol} =26,174.45g_H_{2}

Therefore, the amount of diatomic hydrogen (H_{2}) that is needed to produce 208kg of methanol is 2.62x10^{4}g.

3 0
3 years ago
A solution of 400mg of optically active 2-butanol in 10 mL of water, placed in a 20 cm cell shows an optical rotation of 40o. Wh
labwork [276]

Answer:

Specififc rotation [∝] = 0.5° mL/g.dm

Explanation:

Given that:

mass = 400 mg

volume = 10 mL

For a solution,

The Concentration = mass/volume

Concentration = 400/10

Concentration = 40 g/mL

The path length l = 20 cm = 2 dm

Observed rotation [∝] = + 40°

Specififc rotation [∝] = ∝/l × c

where;

l = path length

c = concentration

Specififc rotation [∝] = (40 / 2 × 40)

Specififc rotation [∝] = 0.5° mL/g.dm

3 0
3 years ago
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