Help please ............on

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1 answer:

SIZIF [17.4K]3 years ago

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A 113L sample of helium at 27°C is cooled at constant pressure to -78.0°C. Calculate the

Ket [755]

Based on information the new volume of the helium is 73.45L.

<h3>New volume of the helium</h3>

Given:

Sample of helium at 27°C=113L

constant pressure=-78.0°C

Let v represent the new volume of the helium

Hence:

113/ 300= v/ 195

Cross multiply

300v=113×195

300v= 22035

Divide both side by 300v

v=22035/300

v=73.45L

Inconclusion the new volume of the helium is 73.45L.

Learn more about new volume of the helium here:brainly.com/question/25830006

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Answer:

i think it is B. but i might be wrong

Explanation:

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