1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
cluponka [151]
3 years ago
9

I need number 7 pls help :))

Mathematics
1 answer:
zubka84 [21]3 years ago
7 0

Answer:

3 pizza

Step-by-step explanation:

four people eat 3/4 of pizza

4*3/4=12/4=3 pizzas

You might be interested in
How much is 160÷43×62
miv72 [106K]

Answer: 230.697

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
what are the first 5 common multiples of 14 and 20? i’ll mark brainliest for whoever answers first!!!
shutvik [7]

Answer:

14, 28, 42, 56, and 70 are the first 5 common multiples of 14

20, 40, 60, 80, and 100 are the first 4 common multiples of 20

8 0
3 years ago
Read 2 more answers
Matthew bought a suitcase marked down from $90 to $81. What is the discount percentage?
Ksivusya [100]

Answer:

10%

Step-by-step explanation:

Percent change= New-Old |Old|× 100% percent change=81-90 |90| × 100= -9 90×100=-10%

7 0
2 years ago
PLZ HELP ASAP!
sineoko [7]

Answer:

The ordered pair (1, 2) is a solution to the system of linear equations.

3 0
3 years ago
From a random sample of 41 teens, it is found that on average they spend 43.1 hours each week online with a population standard
Nadusha1986 [10]

Answer:

Step-by-step explanation:

We want to determine a 90% confidence interval for the mean amount of time that teens spend online each week.

Number of sample, n = 41

Mean, u = 43.1 hours

Standard deviation, s = 5.91 hours

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean +/- z ×standard deviation/√n

It becomes

43.1 ± 1.645 × 5.91/√41

= 43.1 ± 1.645 × 0.923

= 43.1 ± 1.52

The lower end of the confidence interval is 43.1 - 1.52 =41.58

The upper end of the confidence interval is 43.1 + 1.52 =44.62

Therefore, with 90% confidence interval, the mean amount of time that teens spend online each week is between 41.58 and 44.62

8 0
3 years ago
Other questions:
  • A pizza has a diameter of 14 inches what is the approximate circumference
    11·1 answer
  • For the given interval, is the function increasing or decreasing? ​
    7·1 answer
  • Someone please help me with this
    8·1 answer
  • Does anyone know the answer to the question below
    6·1 answer
  • What is the vertex of the graph of f(x) = |x – 13| + 11?
    13·1 answer
  • Timothy purchased a computer for $1,000.
    6·1 answer
  • HELP ASAP, GIVING BRAINLIEST​
    9·1 answer
  • QUICK HELP HURRY MAKRIMG PIEPLE AS BRIANLDIT
    10·2 answers
  • HELP ME PLEASEEEEEEE
    10·1 answer
  • !!! TIME SENSITIVE !!! Determine the period.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!