Answer:
64
Step-by-step explanation:
Find the area of both triangles inside the bigger triangle and add them together.
Use the Pythagorean theorem to find the missing length of the leg in the smallest triangle:
a² + b² = c²
8² + b² = 10²
64 + b² = 100
36 = b²
6 = b
Calculate the area of the smaller triangle:
1/2(<em>b</em>x<em>h</em>)
1/2(6 x 8)
1/2(48)
24
Calculate the area of the bigger triangle:
<em>We know that the longer leg is 10 units because we were able to subtract the length of the smaller triangle's leg from 16.</em>
1/2(<em>b</em>x<em>h</em>)
1/2(10 x 8)
1/2(80)
40
Add both areas to find the area of the largest triangle:
40 + 24 = 64
Answer:
(0, -7)
Step-by-step explanation:
The y-intercept is the point on the line where x = 0 (AKA where the line crosses the y-axis).
Here, the y-intercept is literally given within the question as (0, -7).
Answer:
( 1, -4)
Step-by-step explanation:
To find this answer you go over 2 to the right on the x-axis, then go down 6 on the y-axis. This gives ( 1, -4).
Step-by-step explanation:
Annie = x
Brianna = y
Carly = z
Now,
x + y + z = 105 ...(1)
Carly has sold ten more than three times Brianna's sales.
z = 10 + 3y ...(2)
Brianna sold five more than Annie.
y = 5 + x ...(3)
Now,
z = 10 + 3y
z = 10 + 3(5 + x)
z = 10 + 15 + 3x
z = 25 + 3x
Now,
x + y + z = 105
x + (5 + x) + 25 + 3x = 105
5x + 30 = 105
5x = 105 - 30
5x = 75
5x/5 = 75/5
x = 15
So,
y = 5 + x
y = 5 + 15
y = 20
Now,
z = 25 + 3x
z = 25 + 3(15)
z = 25 + 45
z = 70
Thus,
Annie Sold 15 boxes
Brianna Sold 20 boxes
Carly Sold 70 boxes
Q1. The answers are (–1, 8), (0, 7), (3, 18)
<span>–3x + y ≥ 7
</span>Let's go through all choices:
<span>(–2, –3)
</span>(-3) * (-2) + (-3) ≥ 7
6 - 3 ≥ 7
3 ≥ 7 INCORRECT
(–1, 8)
(-3) * (-1) + 8 ≥ 7
3 + 8 ≥ 7
11 ≥ 7 CORRECT
(0, 7)
(-3) * 0 + 7 ≥ 7
0 + 7 ≥ 7
7 ≥ 7 CORRECT
(1, 9)
(-3) * 1 + 9 ≥ 7
-3 + 9 ≥ 7
6 ≥ 7 INCORRECT
(3, 18)
(-3) * 3 + 18 ≥ 7
-9 + 18 ≥ 7
9 ≥ 7 CORRECT
Q2. The answers are:
5x + 12y ≤ 80
x ≥ 4
<span>y ≥ 0
</span>
<span>x - small boxes
</span><span>y - large boxes
</span>He has x small boxes that weigh 5 lb each and y large boxes that weigh 12 lb each <span>on a shelf that holds up to 80 lb:
5x + 12y </span>≤ 80
Jude needs at least 4 small boxes on the shelf: x ≥ 4
Let's check if y can be 0:
5x + 12y ≤ 80
5x + 12 * 0 ≤ 80
5x + 0 ≤ 80
5x ≤ 80
x ≤ 80 / 5
x ≤ 16
x ≥ 4 can include x ≤ 16
So, y can be 0: y ≥ 0
