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VARVARA [1.3K]
3 years ago
12

Find the value of x .

Mathematics
2 answers:
ohaa [14]3 years ago
7 0

Answer:

x=18

Step-by-step explanation:

(4x-11)\\(2x+25)

According to the Alternate Exterior Angles Theorem, "when two lines are cut by a transversal, the resulting alternate exterior angles are congruent."

This means that the two expressions above are to be set equal to each other because they are representative of two alternate exterior angles, which are congruent:

4x-11=2x+25

Add 11 to both sides of the equation:

4x=2x+36

Subtract 2x from both sides of the equation:

2x=36

Divide both sides of the equation by the coefficient of x, which is 2:

x=18

~

Check your work by substituting 18 for x in the initial equation:

4(18)-11=2(18)+25

61=61

It's correct!

zlopas [31]3 years ago
3 0

Answer:

18

Step-by-step explanation:

From the given figure, we can see that angle (4x - 11) will be equal to angle 1 since they are corresponding angles

We notice that angle 1 is vertically opposite to angle (2x + 25)

Hence,

angle (4x - 11) = angle 1 = angle (2x + 25)

So, we can say that angle (4x - 11) = angle (2x + 25)

Now, solving for x:

4x - 11 = 2x + 25

2x = 36

x = 18

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Read 2 more answers
A line passes through point A(10,15). A second point on the line has an x-value that is 125% of the x-value of point A and a y-v
melisa1 [442]

The equation of the line in the point-slope form is y - 15 = -\frac{3}{2} (x - 10)

Step-by-step explanation:

The point-slope form of a linear equation is y-y_{1}=m(x-x_{1}) , where

  • m is the slope of the line, where m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} , (x_{1},y_{1}) and (x_{2},y_{2}) are two points on the line
  • (x_{1},y_{1}) is a point on the line

∵ Point A = (10 , 15)

∵ The x-coordinate of the second point is 125% of x-coordinate

  of point A

∴ x-coordinate of second point = \frac{125}{100} × 10

∴ x-coordinate of second point = 12.5

∵ The y-coordinate of the second point is 75% of y-coordinate

  of point A

∴ y-coordinate of second point = \frac{75}{100} × 15

∴ y-coordinate of second point = 11.25

∴ The coordinates of the second point are (12.5 , 11.25)

Let us find the slope of the line by using the rule of it above

∵ (x_{1},y_{1}) = (10 , 15)

∵ (x_{2},y_{2}) = (12.5 , 11.25)

∴ m=\frac{11.25-15}{12.5-10}=\frac{-3.75}{2.5}=-\frac{3}{2}

Now we can write the equation

∵ The point-slope form is y-y_{1}=m(x-x_{1})

∵ m=-\frac{3}{2}

∵ (x_{1},y_{1}) = (10 , 15)

- Substitute these values in the form of the equation

∴ y - 15 = -\frac{3}{2} (x - 10)

The equation of the line in the point-slope form is y - 15 = -\frac{3}{2} (x - 10)

Learn more:

You can learn more about the linear equation in brainly.com/question/4152194

#LearnwithBrainly

5 0
3 years ago
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