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DIA [1.3K]
3 years ago
7

Order 3, -4,7,-1 and -6 from least to greatest

Mathematics
2 answers:
Debora [2.8K]3 years ago
8 0
answers -6, -4, -1, 3, 7
katrin [286]3 years ago
5 0
-6, -4, -1, 3, 7

Hope this helps!
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Write an equation of a line parallel to line EF below in slope-intercept form that passes through the point (2, 6).
N76 [4]

Answer:

y = -⅔x + ²²/₃  

Step-by-step explanation:

1. Calculate the slope of EF

Assume E is at (-2, 5) and F is at (1, 3).

m₁ = (y₂ - y₁)/(x₂ - x₁) = (3 - 5)/(1 -(-2)) = -⅔

2. Calculate the slope of the parallel line

m₂ = m₁ = -⅔

3. Calculate its y-intercept

y = mx + b

6 =-⅔(2) + b

Simplify

6 = -⁴/₃ + b

Add ⁴/₃ to each side

b = 6 + ⁴/₃ = ¹⁸/₃ + ⁴/₃ = ²²/₃

The y-intercept is at (0,²²/₃).

4. Write the equation for the line

y = -⅔x + ²²/₃

The diagram shows EF in red. The parallel line in black passes through (2, 6) with a y-intercept at (0,²²/₃).

7 0
3 years ago
The price of a certain computer stock t days after it is issued for sale is p(t)=100+20t−6t^2 dollars. The price of the stock in
Elanso [62]

Answer:

0 < t < \frac{5}{3}

After 1.67 days the stocks would be sold out.

Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

p(t) = 100 + 20t - 6t²

Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = \frac{20}{12}

t = \frac{5}{3} days

Therefore, there are two intervals in which the given function is defined

(0, \frac{5}{3}) and (\frac{5}{3}, ∞)

For the interval (0, \frac{5}{3}),

p'(1) = 20 - 12(1) = 20

For the interval (\frac{5}{3}, ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, \frac{5}{3}) indicates that the function is increasing.

0 < t < \frac{5}{3}

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

7 0
3 years ago
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