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3 years ago

To which subsets does 15/5 belong?

Mathematics

1 answer:

Alexus [3.1K]3 years ago

7 0

Answer:

Whole, natural, integer, rational, real

Step-by-step explanation:

15/5 can be rewritten as 3.

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7/5 mm x 5/14 mm what is the answer

swat32

Answer:

35/70

Step-by-step explanation:

7x5=35

5/14=70

35/70

You can symplify to 1/2

5 0

2 years ago

Read 2 more answers

What does X equal in the equation 8(4-x) =7x +2

drek231 [11]

Answer:

x = 2

Step-by-step explanation:

Given

8(4 - x) = 7x + 2 ← distribute parenthesis on left side

32 - 8x = 7x + 2 ( subtract 7x from both sides )

32 - 15x = 2 ( subtract 32 from both sides )

- 15x = - 30 ( divide both sides by - 15 )

x = 2

4 0

3 years ago

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Is liters length metric, volume, or weight

jekas [21]

Answer/Step-by-step explanation:

Liters are used in the metric system to define amounts of volume.

1 quart = 0.946 metric liters

1 gallon = 3.785 metric liters

3 0

3 years ago

Simply sixteen squared divided by four cubed

FinnZ [79.3K]

You mean "Simplify 16²÷4³?"
16²=16*16, 16= 4*4
4³=4*4*4
so:
Simplify: 16² = 16*16 = 4*4*4*4 = 4 = 4
4³ = 4*4*4 = 4*4*4 1
OR
256 ÷ 64 = 4

6 0

3 years ago

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Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

3 0

3 years ago