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3 years ago

14

Answer quick please I only have 10 more minutes and I still have 10 questions

1 answer:

denis23 [38]3 years ago

6 0

the three one which is waves

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What is the end behavior of the function?

Vinil7 [7]

Answer:

X->-infinite, graph is positive +(infinite)

X-> + infinite, graph is negative (-infinite)

Step-by-step explanation:

When you study end behaviour of a polynomial, you verify it's highest exponent. If it is odd, like this exercise, it's Y values come from negative infinity to positive infinity. If the coefficient is negative, it is the opposite, it comes from positive infinite to negative infinite.

7 0

3 years ago

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Which rules define the function graphed below?

NemiM [27]

Answer:

y=x+2; y=5

Step-by-step explanation:

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2 years ago

2 6/8 in simplest form

Vesna [10]

Answer:

2 3/4

Step-by-step explanation:

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3 years ago

Three landmarks of baseballachievement are Ty Cobb’s batting average of 0.420 in 1911,Ted Williams’s 0.406 in 1941, and George B

harina [27]

Answer:

Ted Williams has the highest standardized score, hence Williams is the best of the three

Cobb is the second highest and hence, the better player

George Brett is third

Step-by-step explanation:

Given the data:

Decade : 1910 __ 1940 ____ 1970

Mean, μ: 0.266 __0.267 ___ 0.261

S/dev, σ : 0.0371 _ 0.0326 __ 0.0317

To compute the standard unit for batting averages, we obtain the standardized score for each of Cobb,Williams, and Brett.

Standardized score (Zscore) : (x - μ) / σ

Cobb, x = 0.420

Ted Williams, x = 0.406

George Brett, x = 0.390

COBB:

Zscore = (0.420 - 0.266) / 0.0371 = 4.1509

Ted Williams :

Zscore = (0.406 - 0.267) / 0.0326 = 4.2638

George, Brett = (0.390 - 0.261) / 0.0317 = 4.0694

Ted Williams has the highest standardized score, hence Williams is the best of the three

Cobb is the second highest and hence, the better player

George Brett is third

6 0

2 years ago

Explain how the distance formula can prove Pythagoras' Theorem. In your

Paul [167]

Answer:

Given a triangle ABC, Pythagoras' Theorem shows that:

$c^2=a^2+b^2$

Thus,

$c = \sqrt{a^2+b^2}$

The distance formula, gives an equivalent expression based on two points at the end of the hypotenuse for a triangle.

$d^2 = (x_{2} -x_{1})^2 + (y_{2} -y_{1})^2$

$d = \sqrt{(x_{2}-x_{1})^2 + (y_{2} -y_{1})^2 }$

Therefore when given the hypotenuse with endpoints at

$(x_{1}, y_{1}) and {(x_{2}, y_{2})$

We know that the third point of the right triangle will be at

$(x_{2}, y_{1})$

and that the two side lengths will be defined by the absolute values of:

$(x_{2} - x_{1}) = a$

$(y_{2} - y_{1}) = b$

8 0

2 years ago