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Pepsi [2]
3 years ago
14

Find each sum.Write in simplest form. 2/6+3/6= 3/8+3/8= 1/4+1/4= 5/12+3/12

Mathematics
1 answer:
Svet_ta [14]3 years ago
4 0
2/6+3/6= 5/6
3/8+3/8= 3/4
1/4+1/4= 1/2
5/12+3/12= 2/3

Hope this helps
You might be interested in
What is the present value of 6000 received 14 years from today when the interest rate is 10%
likoan [24]

Answer:

$14400

Step-by-step explanation:

Given data

Principal= 6000

Time= 14 years

Rate= 10%

Let us use the simple interest expression to find the final amount

A=P(1+rt)

substitute

A=6000(1+0.1*14)

A=6000(1+1.4)

A=6000*2.4

A=$14400

Hence based on a simple interest model the final amount is $14400

3 0
2 years ago
Find the product of 8x93 using distributive property. Show the steps and the solution
lesya692 [45]

Explanation:

Distributive property: → a(b+c)=ab+ac

Multiply by the numbers from left to right.

93*8=744

Then, you can also divide into the numbers.

744/8=93

744/93=8

Product it's going to be multiply by the numbers, fractions, factors, and multiples.

Hope this helps!

Thanks!

Have a great day!

3 0
3 years ago
Read 2 more answers
f(x) has domain , and range . A 2-column table with 5 rows. Column 1 is labeled x with entries negative 4, negative 2, 0, 2, 4.
laiz [17]

Answer:

Domain: {-4, -2, 0, 2, 4}

Range: {-2, -1, 0 1, 2}

Step-by-step explanation:

5 0
3 years ago
Carry out three steps of the Bisection Method for f(x)=3x−x4 as follows: (a) Show that f(x) has a zero in [1,2]. (b) Determine w
ELEN [110]

Answer:

a) There's a zero between [1,2]

b) There's a zero between [1.5,2]

c) There's a zero between  [1.5,1.75].

Step-by-step explanation:

We have f(x)=3^x-x^4

A)We need to show that f(x) has a zero in the interval [1, 2]. We have to see if the function f is continuous with f(1) and f(2).

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(2)=3^2-(2)^4=9-16=(-7)

We can see that f(1) and f(2) have opposite signs. And f(1)>f(2) and the function is continuous, this means that exists a real number c between the interval [1,2] where f(c)=0.

B)We have to repeat the same steps of A)

For the subinterval [1,1.5]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1) and f(1.5) have the same signs, this means there's no zero in the subinterval [1,1.5].

For the subinterval [1.5,2]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.5) and f(2) have opposite signs, this means there's a zero between the subinterval [1.5,2].

C)We have to repeat the same steps of A)

For the subinterval [1,1.25]:

f(x)=3^x-x^4\\\\f(1)=3^1-(1)^4=3-1=2\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5

f(1) and f(1.25) have the same signs, this means there's no zero in the subinterval [1,1.25].

For the subinterval [1.25,1.5]:

f(x)=3^x-x^4\\\\f(1.25)=3^1^.^2^5-(1.25)^4=3.94-2.44=1.5\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13

f(1.25) and f(1.5) have the same signs, this means there's no zero in the subinterval [1.25,1.5].

For the subinterval [1.5,1.75]:

f(x)=3^x-x^4\\\\f(1.5)=3^1^.^5-(1.5)^4=5.19-5.06=0.13\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)

f(1.5) and f(1.75) have opposite signs, this means there's a zero between the subinterval [1.5,1.75].

For the subinterval [1.75,2]:

f(x)=3^x-x^4\\\\f(1.75)=3^1^.^7^5-(1.75)^4=6.83-9.37=(-2.54)\\\\f(2)=3^2-(2)^4=9-16=(-7)

f(1.75) and f(2) have the same signs, this means there isn't a zero between the subinterval [1.75,2].

The graph of the function shows that the answers are correct.

6 0
3 years ago
The outside of a picture frame measures 14 in and 20 in 196in^2 of the picture shows find the thickness of the frame
LuckyWell [14K]
The described picture frame can be visualized into two separate parts. The first area is equal to the area using the outermost dimensions for the length and width. 
             Area = Length x Height
              Area = (20 in) x (14 in) 
              Area = 280 in²

We are given that the area is only equal to 192 in². We subtract this value from the computed area.
         Difference = 280 in² - 192 in²
               difference = 88 in²

This area is equal to the area of the hollow space inside the frame. That is equal to,
      height = 20 in - 2x
      length = 14 in - 2x

The area,
               88 = (20 - 2x)(14 - 2x)

Simplify the right hand side of the equation.
             88 = 280 - 68x + 4x²

Divide the equation by 4,
            22 = 70 - 17x + x²

Transposing,
                x² - 17x - 48 = 0
The factors of the equation is 58.2. 

Thus, the thickenss is equal to 58.2 in
5 0
3 years ago
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