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RUDIKE [14]
3 years ago
11

1. A farmer is planting a 47-acre field of green beans. How many seeds must be purchased if the farmer plants 140,000 seeds per

acre?
Mathematics
1 answer:
Sedaia [141]3 years ago
6 0

Answer:

Step-by-step explanation:

There are 47 acres and the farmer is planting 140,000 per acre.

You got to times 140,000 by 47 but you can multiply 14 by 47 instead and place the zero later.

So take 10 times 47 and that is 470

Then take 4 times 47 and that is 188

Add 470 and 188 and you get 658

Take 658 a place the four zeros and you get 6,580,000 seed

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Please helppp why is he right or wrong!!
bagirrra123 [75]

Answer:

We cannot agree with Andre because x = 3.

Step-by-step explanation:

Assuming the diagram is a weighing scale which can also be represented as an equation having two sides that is balanced. We can express the situation as follows using equation:

x + 2 = 5

Solve for x

x + 2 - 2 = 5 - 2 (subtraction property of equality)

x = 3

If you plug in the value of x on the diagram given, the scale becomes balance on each side.

Therefore, x = 3. Andre is wrong and we cannot agree with Andre.

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3 years ago
there has to be at least one operating path. Once a component fails on a path, that path is no longer operating. The reliability
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Answer:

R = P(R_1) P(R_2|R_1) P(R_3|R_2)*....*P(R_n |R_1,..., R_{n-1}

For this case the reliability of the sytem would be given by:

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And replacing we got:

R = 0.95*0.95*0.5*0.79*0.6= 0.21389

Step-by-step explanation:

We can assume that the system work in series

If we have in general n units the reliability of the system is the probability that unit 1 succeeds and unit 2 succeeds and all of the other units in the system succeed. fror n units must succeed for the system to succeed. The reliability of the system is then given by:

R = P(R_1) P(R_2|R_1) P(R_3|R_2)*....*P(R_n |R_1,..., R_{n-1}

For this case the reliability of the sytem would be given by:

R= \prod_{i=1}^n R_i

R1= 0.95, R2 =0.95, R3= 0.5, R4 = 0.79 , R5 = 0.6

And replacing we got:

R = 0.95*0.95*0.5*0.79*0.6= 0.21389

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