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Rainbow [258]
3 years ago
15

Henry and Elizabeth were both baking apple pies for the town fair. Henry bought 2.6 pounds of Honeycrisp apples that cost $2.15

per pound. Elizabeth purchased 3.5 pounds of Granny Smith apples that cost $1.68 per pound. How much more did Elizabeth spend on apples?
Mathematics
1 answer:
Deffense [45]3 years ago
8 0

Answer:

Well if you multiply 3.5 * 1.68 wich is the amount of pounds you get the amount she spent on apples! I hope this is what you need and that this helps!

Step-by-step explanation:

3.5 * 1.68 =5.88

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2 years ago
A movie collector has 105 movie posters and 90 band posters if she sells 21 movie posters then how many band posters should she
kotykmax [81]

Hi there! :)

<u>Answer:</u>

In order to maintain the same ratio, she should sell 18 band posters.


<u>Step-by-step explanation:</u>

<u>Initial ratio:</u>

Ratio is: 105 movie posters for 90 band posters = <u>105 : 90</u>


She sells 21 movie posters, which means that we are left with 105 movies minus the 21 she sold.

105 - 21 = 84 → She now has <u>84</u> movie posters.


In order to answer your question, you'll need to use the cross product method:

105 movie posters → 90 band posters

84 movie posters  → X

<u>(90 × 84)</u> ÷ 105 = X

<u>7,560 ÷ 105</u> = X

72 = X ⇒ Number of band posters she should have left to maintain the same ratio.

She has 90 band posters :

90 <u>- X</u> = 72

Add "X" to each side of the equation → 72 + X = 72 + X

90 = <u>72</u> + X

Subtract 72 from each side of the equation → 90 - 72 = 18

<u>18 = X</u>


There you go! I really hope this helped, if there's anything just let me know! :)

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If a 32g serving of pasta contains 8g of protein how many grams of protein are in 454g box of the pasta?
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The rectangular prism shown has a length of 5 cm, a height of 3 cm, and the width of 4 cm. What is the surface area of this pris
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Answer:20

Step-by-step explanation:

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Use the graph of y =g(x) to graph the given function.
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Answer:

See image attached

Step-by-step explanation:

This type of transformation corresponds to a reflection of the function's graph around the x axis. Therefore one should obtain the mirror image of the segments on he upper quadrant as shown in red in the attached image.

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