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Alla [95]
3 years ago
9

Help and Explain please

Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0
The answer is b because 10.5 x 10.5 x 12 = 1323
Rudiy273 years ago
4 0
The answer is B. Just multiply all of them then divide
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Calculate the midpoint of the line segments joining the two points (-8, -7) and (4,9)
dmitriy555 [2]

Answer:

Step-by-step explanation:

To calculate the midpoint, you need to plug in the values of x and y into the midpoint formula.

M ( x1 + x2/2 , y1 + y2/2)

M [ -8 + 4/2 , -7 + 9/2]

M ( -2, 1)  

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2 years ago
A clock is positioned on an auditorium wall with its center 9 ft above the floor. The second hand on the clock is 10 inches long
oee [108]

Answer:

B : y=5/6cos(pi/30x)+9

Step-by-step explanation:

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7 0
3 years ago
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Solve the riddle i am 6 more than 2 times 9 what number am i now make up your own riddle for the number 68
Lesechka [4]

The riddle answer is 24.

A riddle for the number 68 is: 12 more than 14 times 4


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2 years ago
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What is the volume of the box?
Agata [3.3K]
To find the volume of the box you have to do the formula for volume

the formula for volume is lxwxh aka length x width x height

so first you have to do 3/4 x 1/2

3/4 x 1/2 = 3/8

Next, you have to do 3/8 x 1/4

3/8 x 1/4 = 3/32

so the volume of the box is 3/32

HOPE THIS HELPS!!!
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3 years ago
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Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime
Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46

The standard error is

s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194

The t-statistic is

t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52

The degrees of freedom are

df=n_1+n_2-2=9+9-2=16

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

5 0
2 years ago
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