Help with FLVS algebra 1 dba questions?? It's urgent!!!

Audrey deposited $40,000 in a savings account with simple interest. Five years later, she had earned $30,000 in interest. What w

Fittoniya [83]

$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&\$30000\\ P=\textit{original amount deposited}\dotfill & \$40000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &5 \end{cases} \\\\\\ 30000=(40000)(\stackrel{\%}{\frac{r}{100}})(5)\implies \cfrac{30000}{(40000)(5)}=\cfrac{r}{100}\implies \cfrac{3}{20}=\cfrac{r}{100} \\\\\\ \cfrac{300}{20}=r\implies \stackrel{\%}{15}=r$

4 0

2 years ago

Using a compass, construct an accurate copy of triangle DEF. Check that EF = 4.6 cm.

MaRussiya [10]

Step-by-step explanation:

construct 90° then measure 4.6 cm and draw a line from F to D

5 0

2 years ago

A submarine dives 300 feet every 2 minutes, and 6,750 feet every 45 minutes. Solve for A and

Gelneren [198K]

A: To find the rate in feet per minute, we can use the information given.
Every two minutes, the submarine dives 300 feet. So
$\frac{300feet}{2minutes} = 150 \frac{feet}{minute}$ .
In order to confirm that our rate is correct, we can use the second set of information given.
$\frac{6750feet}{45minutes}$ = $150 \frac{feet}{minute}$ .
Since we know that the rate is 150 feet per minute, we can multiply it by any number of minutes and get the answer of how deep the submarine is. We can use a variable x to represent the number of minutes and y to represent the depth in feet.
$y=150x$
There's our equation.
B: It would be more reasonable to use an equation with the rate feet per minute because it is more accurate since the time interval isn't too big.

3 0

2 years ago

A triangle has side lengths of 34 in., 20 in., and 47 in. Classify it as acute, obtuse, or right.

Anestetic [448]

34^2 + 20^2 = 1156 + 400 = 1556

47^2 = 2209

because the squares of the 2 smaller sides is less than the square of the longer side the triangle is Obtuse

3 0

2 years ago

What is the minimum number of bits required to store each binary string of length 50? (b) what is the minimum number of bits req

antiseptic1488 [7]

In order to answer the above question, you should know the general rule to solve these questions.
The general rule states that there are 2ⁿ subsets of a set with n number of elements and we can use the logarithmic function to get the required number of bits.
That is:
log₂(2ⁿ) = n number of bits

a). What is the minimum number of bits required to store each binary string of length 50?

Answer: In this situation, we have n = 50. Therefore, 2⁵⁰ binary strings of length 50 are there and so it would require:

log₂(2⁵⁰) = 50 bits.

b). what is the minimum number of bits required to store each number with 9 base of ten digits?

Answer: In this situation, we have n = 50. Therefore, 10⁹ numbers with 9 base ten digits are there and so it would require:

log2(109)= 29.89
 = 30 bits. (rounded to the nearest whole #)

c). what is the minimum number of bits required to store each length 10 fixed-density binary string with 4 ones?

Answer: There is (10,4) length 10 fixed density binary strings with 4 ones and
so it would require:
log₂(10,4)=log₂(210) = 7.7
= 8 bits. (rounded to the nearest whole #)

4 0

2 years ago