8(5) - 4y = 39
40 - 4y = 39
-4y = -1, y = 1/4
Solution: y = 1/4
Answer:
The $1 belongs to the cash box
Step-by-step explanation:
Given
See attachment for complete question
Required
Determine if the $1 belongs to the cash box or not
Represent singles with s and couples with c.
From the attachment, we have:
--- total attendance
--- ticket sold
Solve for s and c.
Make s the subject in (1)
Substitute 47 - c for s in (2)
Open bracket
This means that the total individual which makes up the couples are 35. This is not possible because couples are in 2's and the total should be an even number.
<em>So, we can conclude that the $1 belongs to the cash box</em>
Answer:
-0.6309
Step-by-step explanation:
Using the change of base formula,
Log 1/2 to base 3 = Log1/2 ÷ Log 3 = Log 0.5 ÷ Log 3
Log 0.5 = -0.3010
Log3 = 0.4771
Log 0.5 ÷ Log 3 = -0.3010 ÷ 0.4771 = -0.6309
<span><span> <span>Akar akar persamaan kuadrat 2x² - 3x -1 = 0 adalah x1 dan x2. Persamaan kuadrat baru yang akar akarnya satu lebih kecil dari dua kali akar akar persamaan kuadrat di atas adalah ........</span></span><span><span><span>A.x² - x - 4 = 0</span><span>B.x² + 5x - 4 = 0</span><span>C.x² - x + 4 = 0</span></span><span><span>D.x² + x + 4 = 0</span><span>E.x² - 5x - 4 = 0</span></span></span><span>Jawaban : A
Penyelesaian :
Akar-akar persamaan lama : x1 dan x2
Akar-akar persamaan baru : xA dan xB
xA = 2x1 - 1
xB = 2x2 - 1
xA + xB = (2x1 - 1) + (2x2 - 1)
= 2 (x1 + x2) - 2
= 2 () - 2
= 3 - 2
xA + xB = 1
xA . xB = (2x1 - 1) (2x2 - 1)
= 4 x1.x2 - 2(x1 + x2) + 1
= 4.(-) - 2() + 1
= -2 - 3 + 1
xA . xB = -4
Jadi persamaan kuadrat baru : x² - (xA + xB)x + xA . xB = 0
x² - x - 4 = 0
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