Question

Integration of the following function

Answer 1

Answer: None of the above

Step-by-step explanation:

Given

$\frac{\mathrm{d} \bar{c}}{\mathrm{d} x}=-6x^{-2}+\frac{1}{6}$

$d\bar{c}=\left ( -6x^{-2}+\frac{1}{6}\right )dx$

Now, integrating both sides

$\int d\bar{c}=\int \left ( -6x^{-2}+\frac{1}{6}\right )dx$

$\bar{c}=-6\frac{x^{-2+1}}{-2+1}+\frac{1}{6}x+k_1$

$\bar{c}=6x^{-1}+\frac{1}{6}x+k_1$