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ludmilkaskok [199]
3 years ago
13

0.75,1/2,0.4, and 1/5 from least to greatest

Mathematics
2 answers:
OLEGan [10]3 years ago
8 0

Answer: 1/5,0.4,1/2,0.75

Step-by-step explanation:    

avanturin [10]3 years ago
6 0
0.4, 0.75, 1/2, 1/5
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Please help me asap<br><br>​
dimaraw [331]
Okay so basically 1 + 5 = 180
and if we know 1 = 124 we can assume 5 = 56
and 5 = 4 SOOOO
4 = 56
4 0
3 years ago
How do you find the distance between -2 and 3 on a number line
Masteriza [31]

If you draw the line and mark -2 and 3 you find that they are 5 apart. By calculation, subtract the lowest from the highest: 3 - -2 = 3+2 = 5

6 0
2 years ago
Read 2 more answers
A truck is carrying cranberry juice, grape juice, and pineapple juice bottles in a ratio of
satela [25.4K]

Answer:

140

Step-by-step explanation:

7- Cranberry

2:Grape = 40 so 40/2 = 1

3:Pineapple

1= 20 juices

7+2+3 is 12

20 x 12 is 140

8 0
2 years ago
Read 2 more answers
Last term of the arithmetic progression 8,15,22 is 218. Find<br>the number of terms.​
icang [17]

Answer:

31 terms.

Step-by-step explanation:

218 = 8 +  (n-1)7

210 = (n-1)7

30 + n-1

n = 31

There would be 31 terms in the given AP.

7 0
3 years ago
We measure the diameters for a random sample of 25 oak trees in a neighbourhood. Diameters of oak trees in the neighbourhood fol
jarptica [38.1K]

Answer:

The required confidence inteval = 94.9%.

Step-by-step explanation:

Confidence interval: Mean ± Margin of error

Given: A confidence interval for the true mean diameter of all oak trees in the neighbourhood is calculated to be (36.191, 42.969).

i.e.  Mean + Margin of error = 42.969               (i)

Mean - Margin of error = 36.191                    (ii)

Adding (i) and (ii), we get

2Mean =79.16\\\\\Rightarrow\ Mean= 39.58

Margin of error = 42.969-39.58             [from (i)]

= 3.389

Margin of error = t^* \dfrac{\sigma}{\sqrt{n}}

here n= 25 , \ \sigma=8.25

i.e.

3.389=t^*\dfrac{8.25}{5}\\\\\Rightarrow\ t^* = \dfrac{3.389}{1.65}\\\\\Rightarrow\ t^* =2.0539 \

Using  excel function 1-TDIST.2T(2.054,24)

The required confidence inteval = 94.9%.

7 0
2 years ago
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