All categories

3 years ago

Solve each equation l x+11 l=8 l 3x-2 l=16

1 answer:

3 0

|x + 11| = 8
x + 11 = 8
 -11 -11
 x = -3

|3x - 2| = 16
3x + 2 = 16
 -2 -2
 3x = 14
 3 3
 x = 4 2/3

You might be interested in

49,52,52,52,55,55,74,67 find Q3

Gelneren [198K]

Answer:

Answer:

Quartile Statistics

First Quartile Q1 = 52

Second Quartile Q2 = 53.5

Third Quartile Q3 = 61

Interquartile Range IQR = 9

Median = Q2 x˜ = 53.5

Minimum Min = 49

Maximum Max = 74

Range R = 25

Step-by-step explanation:

8 0

3 years ago

17x-3y=4 2x-4y=1 the solution to the system of equations is

Burka [1]

ANSWER

$x=\frac{13}{62}$

and

$y= \frac{-9}{62}$ e have

EXPLANATION

$17x-3y=4---(1)$

$2x-4y=1$

Let us make y the subject and call it equation (2)

$2x=1+4y$

$x=\frac{1}{2}+2y--(2)$

We put equation (2) in to equation (1)

$17(\frac{1}{2}+2y)-3y=4$

$\frac{17}{2}+34y-3y=4$

$34y-3y=4- \frac{17}{2}$

Simplify to get,

$31y= \frac{8-17}{2}$

$31y= \frac{-9}{2}$

Divide both sides by 31,

$y= \frac{-9}{2} \div 31$

$y= \frac{-9}{2} \times \frac{1}{31}$

$y= \frac{-9}{62}$

We put this value in to equation (2) to get,

$x=\frac{1}{2}+2\times -\frac{9}{62}$

$x=\frac{1}{2} -\frac{18}{62}$

We collect LCM to obtain,

$x=\frac{31-18}{62}$

$x=\frac{13}{62}$

7 0

3 years ago

What is the value of 24x -60

Aleksandr [31]

Answer:

-1440

Step-by-step explanation:

24x -60 = -1440

3 0

3 years ago

Can someone help please !! I appreciate it

kkurt [141]

ANSWER
x=2
EXPLANATION
I’m smart don’t worry

7 0

3 years ago

Read 2 more answers

Assume that the paired data came from a population that is normally distributed. using a 0.05 significance level and dequalsxmin

Artemon [7]

"Assume that the paired data came from a population that is normally distributed. Using a 0.05 significance level and d = (x - y), find $\bar{d}$ , $s_{d}$ , the t-test statistic, and the critical values to test the claim that $\mu_{d} = 0$ "

You did not attach the data, therefore I can give you the general explanation on how to find the values required and an example of a random paired data.

For the example, please refer to the attached picture.

A) Find $\bar{d}$
You are asked to find the mean difference between the two variables, which is given by the formula:
$\bar{d} = \frac{\sum (x - y)}{n}$

These are the steps to follow:
1) compute for each pair the difference d = (x - y)
2) sum all the differences
3) divide the sum by the number of pairs (n)

In our example:
 $\bar{d} = \frac{6}{8} = 0.75$ 

B) Find $s_{d}$
You are asked to find the standard deviation, which is given by the formula:
 $s_{d} = \sqrt{ \frac{\sum(d - \bar{d}) }{n-1} }$

These are the steps to follow:
1) Subtract the mean difference from each pair's difference
2) square the differences found
3) sum the squares
4) divide by the degree of freedom DF = n - 1

In our example:
$s_{d} = \sqrt{ \frac{101.5}{8-1} }$
= √14.5
= 3.81

C) Find the t-test statistic.
You are asked to calculate the t-value for your statistics, which is given by the formula:
$t = \frac{(\bar{x} - \bar{y}) - \mu_{d} }{SE}$

where SE = standard error is given by the formula:
$SE = \frac{ s_{d} }{ \sqrt{n} }$

These are the steps to follow:
1) calculate the standard error (divide the standard deviation by the number of pairs)
2) calculate the mean value of x (sum all the values of x and then divide by the number of pairs)
3) calculate the mean value of y (sum all the values of y and then divide by the number of pairs)
4) subtract the mean y value from the mean x value
5) from this difference, subtract $\mu_{d}$
6) divide by the standard error

In our example:
SE = 3.81 / √8
= 1.346

The problem gives us $\mu_{d} = 0$ , therefore:
t = [(9.75 - 9) - 0] / 1.346
= 0.56

D) Find $t_{\alpha / 2}$
You are asked to find what is the t-value for a 0.05 significance level.

In order to do so, you need to look at a t-table distribution for DF = 7 and A = 0.05 (see second picture attached).

We find $t_{\alpha / 2} = 1.895$ 

Since our t-value is less than $t_{\alpha / 2}$ we can reject our null hypothesis!!

7 0

3 years ago