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alisha [4.7K]
3 years ago
15

Solve the following absolute value inequality. |(5x-4)-3|<0.01

Mathematics
1 answer:
12345 [234]3 years ago
7 0

Answer:

<h2>Step-by-step explanation:</h2><h2>|(5x-4)-3|<0.01</h2><h2>so -0.01<(5x-4-3)<0.01</h2><h2>add 7</h2><h2>7-0.01<5x<7+0.01</h2><h2>6.99<5x<7.01</h2><h2>divide by 5</h2><h2>1.398<x<1.402</h2>
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Simplify the square root of four over the cubed root of four.
Vikki [24]

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\bf \cfrac{\sqrt{4}}{\sqrt[3]{4}}\implies \cfrac{\sqrt[2]{4}}{\sqrt[3]{4}}\implies \cfrac{4^{\frac{1}{2}}}{4^{\frac{1}{3}}}\implies 4^{\frac{1}{2}}\cdot 4^{-\frac{1}{3}}\implies 4^{\frac{1}{2}-\frac{1}{3}}\implies 4^{\frac{3-2}{6}} \\\\\\ 4^{\frac{1}{6}}\implies (2^2)^{\frac{1}{6}}\implies 2^{2\cdot \frac{1}{6}}\implies 2\frac{1}{3}\implies \sqrt[3]{2}

7 0
3 years ago
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HELP, VERY EASY MATHS QUESTION
Helen [10]

Answer:

z=7

Step-by-step explanation:

area = ½ × (a + b) × h.

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3 0
3 years ago
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Travis is in a hot air balloon that has just taken off and is now floating 12 meters above its launching point. Shontal is stand
ozzi

Shontal is at a distance of 13 meters from the launching point

Step-by-step explanation:

Step 1 :

Given,

Distance of Travis from the launching point  = 12 meters

Distance of Shontal from the launching point = 9 meters

Step 2 :

Let A represent the launching point

B represent the point above the launching point at which the balloon is floating.

C represent the point where Shontal stands on the ground.

The angle made by AB with BC is 90 degrees because the balloon is directly above the launching point

Step 3:

So we have a right angle triangle here, with

AB = 12

BC = 9 and angle ABC = 90 degrees

We need to find out length of  AC

Using the theorem of Pythagoras,

AC² = AB² + BC²

AC² = 12² + 9² = 144 + 25 = 169 = 13

Step 4 :

Answer :

Shontal stands at a distance of 13 meters from the launching point

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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tamaranim1 [39]
First you must find the tenths place

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3 years ago
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