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ira [324]
2 years ago
12

A six-ounce paper cup has a hole in the bottom and leaks water. If it was originally full and has only two ounces after 40 minut

es, what is the rate of change of the amount of water in the cup per minute?
1/10 ounces per minute.

-1/10 ounces per minute.

10 ounces per minute

-10 ounces per minute
Mathematics
2 answers:
Sveta_85 [38]2 years ago
6 0
Hey there, 

Lets solve this problem together. 

We know that a <span>six-ounce paper cup has a hole in the bottom and leaks water. If it was originally full and has only two ounces after 40 minutes.
 
</span>(0,6)(40,2)&#10;&#10; (slope) = (2-6) / (40 - 0)&#10;&#10;slope = -4/40&#10;&#10;slope = -1/10 per minute
Pie2 years ago
5 0
(0,6)(40,2)
rate of change (slope) = (2-6) / (40 - 0)
slope = -4/40
slope = -1/10 per minute


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In a batch of 960 calculators, 8 were found to be defective. What is a probability that a calculator chosen at random will be de
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Out of 960 calculators, 8 were found be to defective

Probability:
                 \frac{8}{960}
                 0.00833...
As a Percent:
                 0.00833....× 100
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A fair coin is flipped twelve times. What is the probability of the coin landing tails up exactly nine times?
seraphim [82]

Answer:

P\left(E\right)=\frac{55}{1024}

Step-by-step explanation:

Given that a fair coin is flipped twelve times.

It means the number of possible sequences of heads and tails would be:

2¹² = 4096

We can determine the number of ways that such a sequence could contain exactly 9 tails is the number of ways of choosing 9 out of 12, using the formula

nCr=\frac{n!}{r!\left(n-r\right)!}

Plug in n = 12 and r = 9

       =\frac{12!}{9!\left(12-9\right)!}

       =\frac{12!}{9!\cdot \:3!}

       =\frac{12\cdot \:11\cdot \:10}{3!}            ∵ \frac{12!}{9!}=12\cdot \:11\cdot \:10

       =\frac{1320}{6}                   ∵ 3!\:=\:3\times 2\times 1=6

       =220

Thus, the probability will be:

P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}

         =\frac{220}{4096}

         =\frac{55}{1024}

Thus, the probability of the coin landing tails up exactly nine times will be:

P\left(E\right)=\frac{55}{1024}

4 0
3 years ago
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