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ira [324]
3 years ago
12

A six-ounce paper cup has a hole in the bottom and leaks water. If it was originally full and has only two ounces after 40 minut

es, what is the rate of change of the amount of water in the cup per minute?
1/10 ounces per minute.

-1/10 ounces per minute.

10 ounces per minute

-10 ounces per minute
Mathematics
2 answers:
Sveta_85 [38]3 years ago
6 0
Hey there, 

Lets solve this problem together. 

We know that a <span>six-ounce paper cup has a hole in the bottom and leaks water. If it was originally full and has only two ounces after 40 minutes.
 
</span>(0,6)(40,2)&#10;&#10; (slope) = (2-6) / (40 - 0)&#10;&#10;slope = -4/40&#10;&#10;slope = -1/10 per minute
Pie3 years ago
5 0
(0,6)(40,2)
rate of change (slope) = (2-6) / (40 - 0)
slope = -4/40
slope = -1/10 per minute


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at a meeting ,everyone shakes hands exactly once with every other person . if there are 55 handshakes . then what Is the number
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Every handshake takes 2. If no one shakes hands twice with another, there are 10+1 total people shaking hands (11).

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11— 10 hs

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9— 8 hs

8— 7 hs

7— 6 hs

6— 5 hs

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Total handshakes 55, total people 11.
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3 years ago
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3 years ago
The U.S. Bureau of Labor Statistics reports that of persons who usually work full-time, the average number of hours worked per w
alukav5142 [94]

Answer:

The standard deviation of number of hours worked per week for these workers is 3.91.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

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After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem we have that:

The average number of hours worked per week is 43.4, so \mu = 43.4.

Suppose 12% of these workers work more than 48 hours. Based on this percentage, what is the standard deviation of number of hours worked per week for these workers.

This means that the Z score of X = 48 has a pvalue of 0.88. This is Z between 1.17 and 1.18. So we use Z = 1.175.

Z = \frac{X - \mu}{\sigma}

1.175 = \frac{48 - 43.4}{\sigma}

1.175\sigma = 4.6

\sigma = \frac{4.6}{1.175}

\sigma = 3.91

The standard deviation of number of hours worked per week for these workers is 3.91.

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