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mrs_skeptik [129]
3 years ago
15

I think it’s A am I right

Mathematics
2 answers:
Korolek [52]3 years ago
6 0

\bf \textit{surface area of a cylinder}\\\\ SA=2\pi r(h+r)~~ \begin{cases} r=radius\\ h=height\\ ------\\ r=\stackrel{mm}{4}\\ h=\stackrel{cm}{1.5}\\ ~~~~\stackrel{mm}{15} \end{cases}\implies SA=2\pi (4)(15+4) \\\\\\ SA=8\pi (19)\implies SA=152\pi

Mandarinka [93]3 years ago
4 0

Pi(r)(r)(2) + pi(diameter)(height)

3.14(4)(4)(2)+ 3.14(8)(1.5)

138.16

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Helppp a child out please
Nutka1998 [239]

Answer:

The answer is 35

Step-by-step explanation:

given

an = 3n + 5

a10 = 3 * 10 + 5

= 30 + 5

= 35

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FinnZ [79.3K]

Answer:

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Step-by-step explanation:

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2 years ago
1. Determine if the set of ordered pairs is a relation or a function.
kykrilka [37]

Answer:

This is just a relation.

Step-by-step explanation:

It is easy to see if a set of ordered pairs is a relation or a relation that is a function.

If all the points are distinct, then you just have to look at the x-coordinates.

If all the x-coordinates are different, then it is a function. Otherwise, it is a just a relation.

So this cannot be a function because there is at least two different points that have x=0.

5 0
3 years ago
A ball is thrown up in the air, and it's height (in feet) as a function of time (in seconds) can be written as h(t) = -16t2 + 32
olga2289 [7]

Answer:

1) Using properties of the quadratic equation:

Here the height equation is:

h(t) = -16t^2 + 32t + 6

We can see that the leading coefficient is negative, this means that the arms of the graph will open downwards.

Then, the vertex of the quadratic equation will be the maximum.

Remember that for a general quadratic equation:

a*x^2 + b*x + c = y

the x-value of the vertex is:

x = -b/2a

Then in our case, the vertex is at:

t = -32/(2*-16) = 1

The maximum height will be the height equation evaluated in this time:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

2) Second method, using physics.

We know that an object reaches its maximum height when the velocity is equal to zero (the velocity equal to zero means that, at this point, the object stops going upwards).

If the height equation is:

h(t) = -16*t^2 + 32*t + 6

the velocity equation is the first derivation of h(t)

Remember that for a function f(x) = a*x^n

we have that:

df(x)/dx = n*a*x^(n-1)

Then:

v(t) = dh(t)/dt = 2*(-16)*t + 32 + 0

v(t) = -32*t + 32

Now we need to find the value of t such that the velocity is equal to zero:

v(t) = 0 = -32*t + 32

       32*t = 32

            t = 32/32 = 1

So the maximum height is at t = 1

(same as before)

Now we just need to evaluate the height equation in t = 1:

h(1) = -16*1^2 + 32*1 + 6 = 22

The maximum height is 22ft

4 0
3 years ago
PLEASE ANSWER ASASP!!!!!!<br> 4x + 10 = 30<br> what is x?
sveticcg [70]

Answer:

x=5

Step-by-step explanation:

4x+10=30

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4x=20

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✨Hope this helps!!✨

4 0
3 years ago
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