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3 years ago

Can you guys please help me thanks

Mathematics

1 answer:

Cloud [144]3 years ago

8 0

Sure, the answer is 1 of 3 to the a and the B to K

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If 3/x= 4/5, then what is the value of x?

vitfil [10]

3 4
—- = —-
x 5

cross multiply 3 and 5 = 15
and 4 and x = 4x
you get 15=4x

x= 15/4

5 0

3 years ago

What is $40.39 times x

Iteru [2.4K]

Answer:

$40.39x

Step-by-step explanation:

hope this helpss!!!

5 0

3 years ago

What’s the domain and range of:<br> log(√(2x-1) + 3 )<br> Please explain how you got it too!!

Radda [10]

Two main facts are needed here:

1. The logarithm $\log x$ , regardless of the base of the logarithm, exists for $x>0$ .

2. The square root $\sqrt x$ exists for $x\ge0$ .

(in both cases we're assuming real-valued functions only)

By (2) we know that $\sqrt{2x-1}$ exists if $2x-1\ge0$ , or $x\ge\dfrac12$ .

By (1), we know that $\log(\sqrt{2x-1}+3)$ exists if $\sqrt{2x-1}+3>0$ , or $\sqrt{2x-1}>-3$ . But as long as the square root exists, it will always be positive, so this condition will always be met.

Ultimately, then, we only require $x\ge\dfrac12$ , so the function has domain $\left[\dfrac12,\infty)$ .

To determine the range, we need to know that, in their respective domains, $\sqrt x$ and $\log x$ increase monotonically without bound. We also know that $x=\dfrac12$ at minimum, at which point the square root term vanishes, so the least value the function takes on is $\log3$ . Then its range would be $[\log3,\infty)$ .

3 0

3 years ago

Steve went to Macy's to buy clothing, Steve got to the checkout, and he had

noname [10]

Answer:

$67.41

Step-by-step explanation:

We want to find out how much 30% off of $96.30 is. To do that, we need to first multiply $96.30 to find out how much 30% would be. Don't forget to change 30% into its decimal form (30% - > .3).

96.30 x .3 = 28.89

This means that Steve got $28.89 dollars removed from his final bill. To find the actual final bill, subtract 28.89 from 96.30.

96.30 - 28.89 = $67.41

7 0

3 years ago

Evaluate the limit of

tekilochka [14]

Answer:

Option a is correct -- $\frac{9}{2}$

Step-by-step explanation:

If we put infinity directly into the expression we get ∞ + ∞ expression. In order to circumvent it we divide both numerator and denominator with the greatest exponent.

$\lim_{x \to \infty} \frac{9n^{3}+5n-2}{2n^{3}}$

Divide each term by n³

$=\lim_{x \to \infty} \frac{\frac{9n^{3}}{n^{3}}+\frac{5n}{n^{3}} -\frac{2}{n^{3}}}{\frac{2n^{3}}{n^{3}} }$

$=\lim_{x \to \infty}\frac{9(1)+\frac{5}{n^{2}}-\frac{2}{n^{3}}}{2(1)} } \\=\lim_{x \to \infty}\frac{9+\frac{5}{n^{2}}-\frac{2}{n^{3}}}{2}} \\\\by putting n = infinity \frac{5}{n^{2}} becomes 0 and\frac{2}{n^{3}} becomes 0 \\=\frac{9+0-0}{2} \\=\frac{9}{2}$

4 0

3 years ago