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zloy xaker [14]
4 years ago
7

Hydrogen gas has been suggested as a clean fuel because it produces only water vapor when it burns. If the reaction has a 88.9%

yield, what mass of hydrogen forms 593 kg of water?
Chemistry
1 answer:
GaryK [48]4 years ago
8 0

Answer:

Mass of hydrogen = 667 kg (Approx)

Explanation:

Given:

Mass of water = 593 kg

Yield rate = 88.9%

Find:

Mass of hydrogen

Computation:

Mass of hydrogen =  [Mass of water / Yield rate]100

Mass of hydrogen =  [593 / 88.9]100

Mass of hydrogen = 667.04162

Mass of hydrogen = 667 kg (Approx)

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If an ultraviolet photon has a wavelength of 77.8 nm calculate the energy of one mole ultraviolet photon.
DerKrebs [107]

Answer:

Explanation:

E = (hc)/(λ)

E = (6.624x10^(-27))Js x ((3×10^8)ms^(-1)) /

(77.8x10^(-9)m)

E = 2.55 x 10^(-11) J

7 0
3 years ago
Merits of modern periodic table?​
ANEK [815]

Answer:

<h3>Merits of modern periodic table:</h3>
  • The wrong position of some elements like argon, potassium, cobalt and nickel due to atomic weights have been solved by arranging the elements in the order of increasing atomic number without changing their own places.
  • The isotopes of some element have the same atomic numbers. Therefore, they find the same position in periodic table.
  • It separates metals from non-metals.
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Hope this helps...

Good luck on your assignment...

6 0
3 years ago
Please help! it’s due date is in a few minutes
Licemer1 [7]

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Explanation:

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7 0
3 years ago
A frictionless piston cylinder device is subjected to 1.013 bar external pressure. The piston mass is 200 kg, it has an area of
Bad White [126]

Answer:

a) T_{2} = 360.955\,K, P_{2} = 138569.171\,Pa\,(1.386\,bar), b) T_{2} =  347.348\,K, V_{2} = 0.14\,m^{3}

Explanation:

a) The ideal gas is experimenting an isocoric process and the following relationship is used:

\frac{T_{1}}{P_{1}} = \frac{T_{2}}{P_{2}}

Final temperature is cleared from this expression:

Q = n\cdot \bar c_{v}\cdot (T_{2}-T_{1})

T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{v}}

The number of moles of the ideal gas is:

n = \frac{P_{1}\cdot V_{1}}{R_{u}\cdot T_{1}}

n = \frac{\left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}} \right)\cdot (0.12\,m^{3})}{(8.314\,\frac{Pa\cdot m^{3}}{mol\cdot K} )\cdot (298\,K)}

n = 5.541\,mol

The final temperature is:

T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (30.1\,\frac{J}{mol\cdot K} )}

T_{2} = 360.955\,K

The final pressure is:

P_{2} = \frac{T_{2}}{T_{1}}\cdot P_{1}

P_{2} = \frac{360.955\,K}{298\,K}\cdot \left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}}\right)

P_{2} = 138569.171\,Pa\,(1.386\,bar)

b) The ideal gas is experimenting an isobaric process and the following relationship is used:

\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}}

Final temperature is cleared from this expression:

Q = n\cdot \bar c_{p}\cdot (T_{2}-T_{1})

T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{p}}

T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (38.4\,\frac{J}{mol\cdot K} )}

T_{2} =  347.348\,K

The final volume is:

V_{2} = \frac{T_{2}}{T_{1}}\cdot V_{1}

V_{2} = \frac{347.348\,K}{298\,K}\cdot (0.12\,m^{3})

V_{2} = 0.14\,m^{3}

4 0
4 years ago
An object can become electrically charged if it gains or loses which particles?
Sunny_sXe [5.5K]

Answer:

if it gains or loses neutrons

6 0
3 years ago
Read 2 more answers
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