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ehidna [41]
3 years ago
14

Please help will mark brainliest!

Chemistry
1 answer:
Llana [10]3 years ago
8 0

Answer:

1. desert

2. grasslands

3. rainforest

4. tundra

5. temperate deciduous forest

6. coniferous forest

Explanation:

educated guess, good luck

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What is the concentration of hydrogen ions in a solution of KOH with a pOH of 1.72?
bezimeni [28]

Answer:

[h+]= 5.25e-13

Explanation:

pH= 14-1.72= 12.28

[h+]= 5.25e-13

3 0
3 years ago
how many moles of sodium are needed to react with sulfuric acid to produce 3.75 moles of sodium sulfate according to the followi
anastassius [24]
Hello!
<span>
You'll need to react 7,5 moles of Sodium with sulfuric acid to produce 3.75 moles of sodium sulfate
</span>
First of all, you need to balance the reaction. The balanced reaction is shown below (ensuring that the Law of Conservation of Mass is met on both sides):

2Na + H₂SO₄ → Na₂SO₄ + H₂

Now, all that you have to do is to use molar equivalences in this reaction applying the coefficients to calculate the moles of Sodium that you'll need:

molesNa=3,75moles Na_{2} SO_4* \frac{2 moles Na}{1 mol Na_{2} SO_4} =7,5 moles Na 

Have a nice day!
5 0
3 years ago
A car travels 66 kilometers in 3 hours. what is its speed
Ne4ueva [31]

Answer:

22 kph

Explanation:

You simply divide the distance and the time. 66/3 = 22.

8 0
3 years ago
Read 2 more answers
if .709 j of heat is added to water and cause the temperature to go up by .036 degrees C what mass of water is present
liberstina [14]

Answer:

0.00471 grams H₂O

Explanation:

To determine the mass, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat capacity (J/g°C)

-----> ΔT = temperature change (°C)

The specific heat capacity of water is 4182 J/g°C. You can plug the given values into the equation and simplify to isolate "c".

Q = 0.709 J                            c = 4182 J/g°C

m = ? g                                   ΔT = 0.036 °C

Q = mcΔT                                                    <----- Equation

0.709 J = m(4182 J/g°C)(0.036 °C)            <----- Insert values

0.709 J = m(150.552)                                 <----- Multiply 4182 and 0.036

0.00471 = m                                              <----- Divide both sides by 150.552

8 0
1 year ago
Which of the following statements best describes why a solution of 6.00 g of Ca(NO3)2?in 30.0 g of water has a greater boiling-p
sukhopar [10]
Boiling-point elevation is a colligative property.

That means, the the boiling-point elevation depends on the molar content (fraction) of solute.

The dependency is ΔTb = Kb*m

Where ΔTb is the elevation in the boiling point, kb is the boiling constant, and m is the molality.

A solution of 6.00 g of Ca(NO3) in 30.0 g of water has 4 times the molal concentration of a solution of 3.00 g of Ca(NO3)2 in 60.0 g of water.:

(6.00g/molar mass) / 0.030kg = 200 /molar mass
(3.00g/molar mass) / 0.060kg =   50/molar mass

=> 200 / 50 = 4.

Then, given the direct proportion of the elevation of the boiling point with the molal concentration, the solution of 6.00 g  of CaNO3 in 30 g of water will exhibit a greater boiling point elevation.

Or, what is the same, the solution with higher molality will have the higher boiling point.
5 0
3 years ago
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