Answer:
$30.86
Step-by-step explanation:
28.45+( 28.45*0.085)
28.45+2.41
30.86
QUESTION:
The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.
ANSWER:
Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–
- P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.
Since there are 10 digits to choose from, we can assume that n = 10.
Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.
Now, plug these values into the formula and solve:
= 10!(10−5)!
= 10!5!
= 10⋅9⋅8⋅7⋅6
= 30240.
Answer:
Both proportions are equivalent.
Step-by-step explanation:
We have been given two proportions
and
. We are asked to find why the solutions to our given proportions are equal.
We can solve proportions by cross multiplying them.
After cross multiplying our both proportions we will get same equation that is:
![40*10=8*x](https://tex.z-dn.net/?f=40%2A10%3D8%2Ax)
![400=8x](https://tex.z-dn.net/?f=400%3D8x)
![8*x=40*10](https://tex.z-dn.net/?f=8%2Ax%3D40%2A10)
![8x=400](https://tex.z-dn.net/?f=8x%3D400)
Since we get same equation after cross multiplying both proportions, therefore, the solutions to the given proportions would be same.
To change a decimal to a fraction you need to first place the decimal over 1. Next, for each number behind the decimal, you will multiply by a multiple of 10. Since there are 2 numbers behind the decimal, it's 100. Therefore,
92.96 x 100 = 9296
1 x 100= 100
Your new fraction is 9296/100. Now we simplify it. I'm going by 2's so it may take a bit.
Simplifying it twice by 2's your answer would be:
2324/25
- Initial velocity=u=0m/s
- Distance=s=150m
- Time=t=10s
- Acceleration=a
Using second equation of kinematics
![\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20s%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2)
![\\ \sf\longmapsto 150=0(10)+\dfrac{1}{2}a(10)^2](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20150%3D0%2810%29%2B%5Cdfrac%7B1%7D%7B2%7Da%2810%29%5E2)
![\\ \sf\longmapsto 150=\dfrac{1}{2}\times 100a](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20150%3D%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%20100a)
![\\ \sf\longmapsto 50a=150](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%2050a%3D150)
![\\ \sf\longmapsto a=\dfrac{150}{50}](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20a%3D%5Cdfrac%7B150%7D%7B50%7D)
![\\ \sf\longmapsto a=3m/s^2](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20a%3D3m%2Fs%5E2)
Using newtons second law
![\\ \sf\longmapsto F=ma](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20F%3Dma)
![\\ \sf\longmapsto F=1000(3)](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20F%3D1000%283%29)
![\\ \sf\longmapsto F=3000N](https://tex.z-dn.net/?f=%5C%5C%20%5Csf%5Clongmapsto%20F%3D3000N)